1. Which of the following is an example of a hypothesis?

In order to test for the purity of a specific sample that was synthesized, the melting point of a compound is measured. Basically speaking, the melting point identifies how pure a compound is. There are several cases that are worth noting:

if the measured melting point is significantly lower than theoretical, e. g., lower by 3 or more degrees, we conclude that our compound contains a substantial amount of impurities;
wide range in the melting point indicates impurities, unless it agrees with the theoretical range.

Since our compound is even 10 degrees Celsius lower than expected, it indicates that the compound is significantly impure.

5 0

3 years ago

An atom's configuration based on its number of electrons ends at 3p3. Another atom has nine more electrons. Starting at 3p, what

77julia77 [94]

<h3><u>Answer;</u></h3>

3p34s23d7

<h3><u>Explanation</u>;</h3>

Electrons in an atom are contained in specific energy levels that are different distances from the nucleus.
Within each energy level is a volume of space where specific electrons are likely to be located, called orbitals. Orbitals are of different shapes, denoted by a letter (s, p, d, f, g).
S-orbital takes a maximum of two electrons, p-orbital take a maximum of six electrons, d-orbital takes a maximum of 10 electrons, and so fourth.
The electron filling pattern takes; 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p.........
Therefore; in this case after 3p3, we then go to 4s, with 2 electrons, then 3d which takes 7 electrons.

8 0

3 years ago

Read 2 more answers

A balloon is filled to a volume of 1.50 L with 3.00 moles of gas at 25 °C. With pressure and temperature held constant, what wil

Ludmilka [50]

Answer:

Volume : 1.25 L

Explanation:

We are given here that the volume ( V $_1$ ) = 1.50 Liters, the initial moles ( held at 25 °C ) = 3.00 mol, and the final moles ( n $_2$ ) = 3.00 - 0.5 = 2.5 mol. The final mol is calculated given that 0.50 mol of gas are released from the prior 3.00 moles of gas.

Volume ( V $_1$ ) = 1.50 L,

Initial moles ( n $_1$ ) = 3.00 mol,

Final Volume ( n $_2$ ) = 3.00 - 0.5 = 2.5 mol

Applying the combined gas law, we can calculate the final volume ( V $_2$ ).

P $_1$ V $_1$ / n $_1$ T $_1$ = P $_2$ V $_2$ / n $_2$ T $_2$ - we know that the pressure and temperature are constant, and therefore we can apply the following formula,

V $_1$ / n $_1$ = V $_2$ / n $_2$ - isolate V $_2$ ,

V $_2$ = V $_1$ n $_2$ / n $_1$ = 1.50 L $*$ 2.5 mol / 3.00 mol = ( 1.5 $*$ 2.5 / 3 ) L = 1.25 L

The volume of the balloon will be 1.25 L.

6 0

3 years ago