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Bezzdna [24]
4 years ago
9

Carbon monoxide reacts with oxygen to form carbon dioxide by the following reaction: 2 CO(g) + O2(g) → 2 CO2(g)∆H for this react

ion is −135.28 kcal. How much heat would be released if 12.0 moles of carbon monoxide reacted with sufficient oxygen to produce carbon dioxide? Use only the information provided in this question. 1. 270.56 kcal 2. 1623.36 kcal 3. 811.68 kcal 4. 405.84 kcal 5. 541.12 kcal 6. 135.28 kcal
Chemistry
1 answer:
MrMuchimi4 years ago
4 0

Answer : The amount of heat released would be, (3) 811.68 kcal

Explanation :  Given,

Moles of carbon monoxide = 12.0 mole

Enthalpy change = -135.28 kcal

The given balanced chemical reaction is,

2CO(g)+O_2(g)\rightarrow 2CO_2(g)

From the balanced chemical reaction we conclude that,

As, 2 moles of carbon monoxide react to release heat = 135.28 kcal

So, 12.0 moles of carbon monoxide react to release heat = \frac{12.0}{2}\times 135.28kcal=811.68kcal

Thus, the amount of heat released would be, 811.68 kcal

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Answer:

346.g of solution

Explanation:

In this case, if we have 5.2 % by mass it means that in <u>100 g of the solution we will have 5.2 g of glucose</u>. Therefore we can do the calculation:

<u>5.2 g of glucose = 100 g of solution</u>

18~g~of~glucose\frac{100~g~of~solution}{5.2~g~of~glucose}=346.15~g~of~solution

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This logic can work for all types of solutions. By mass (as in this case), by volume or mass/volume.

I hope it helps!

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A chemist prepares a solution of zinc oxalate by measuring out of zinc oxalate into a volumetric flask and filling the flask to
anyanavicka [17]

<u>Answer:</u> The concentration of zinc oxalate is 1.7\times 10^{-11}M

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}

We are given:

Moles of zinc oxalate = 0.0075\mu mol=7.5\times 10^{-9}mol    (Conversion factor:  1mol=10^{6}\mu mol  )

Volume of solution = 450 mL

Putting values in above equation, we get:

\text{Molarity of solution}=\frac{7.5\times 10^{-9}\times 1000}{450mL}\\\\\text{Molarity of solution}=1.66\times 10^{-11}M=1.7\times 10^{-11}M

In case of multiplication and division, the number of significant digits is taken from the value which has least precise significant digits. Here, the least precise number of significant digits are 2.

Hence, the concentration of zinc oxalate is 1.7\times 10^{-11}M

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