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3 years ago

Which of the following elements would exhibit the greatest shielding effect?

2 answers:

5 0

Rubidium because it is lower on the periodic table and therefore has more electrons to shield the valence electrons from the positive core

Korolek [52]3 years ago

5 0

Answer: Option (D) is the correct answer.

Explanation:

Shielding effect is the effect in which nucleus of an atom is surrounded by number of electrons in such a manner that there will be decrease in attraction between nucleus and valence electrons.

So, more is the number of shells present in an atom more will be its shielding effect. Whereas smaller is the size of atom more will be attraction between its nucleus and valence electrons. So, it would be difficult to remove an electron from the valence shell.

For example, rubidium is larger in size so it has more number of shells and thus more shielding effect.

Thus, we can conclude that out of the given options rubidium would exhibit the greatest shielding effect.

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Describe what happens to water particles when ice melts

Rama09 [41]

Hello there! I'm gladly to help you out! :)

Melting Ice melts when heat energy causes the molecules to move faster, breaking the hydrogen bonds between molecules to form liquid water.

Hope this helped!

4 0

3 years ago

Neeeeeed helpppppp will give brainiest

Artyom0805 [142]

Answer:

I think it is c

Explanation:

When water turns into water vapor it goes into the air so it must be lighter

5 0

3 years ago

Determine the value of the equilibrium constant, Kgoal, for the reactionN2(g)+H2O(g)⇌NO(g)+12N2H4(g), Kgoal=?by making use of th

Black_prince [1.1K]

Answer:

$K_{goal}=1.793*10^{-33}$

Explanation:

N2(g)+O2(g)⇌2NO(g), $K_1 = 4.10*10^{-31}$

N2(g)+2H2(g)⇌N2H4(g), $K_2 = 7.40*10^{-26}$

2H2O(g)⇌2H2(g)+O2(g), $K_3 = 1.06*10^{-10}$

If we add above reaction we will get:

2N2(g)+2H2O(g)⇌2NO(g)+N2H4(g) Eq (1)

Equilibrium constant for Eq (1) is $K_1*K_3*K_3$

Divide Eq (1) by 2, it will become:

N2(g)+H2O(g)⇌NO(g)+1/2N2H4(g) Eq (2)

Equilibrium constant for Eq (2) is $(K_1*K_3*K_3)^{1/2}$

$Equilibrium constant =K_{goal}= (K_1*K_2*K_3)^{1/2}\\K_{goal}= (4.10*10^{-31} *7.40*10^{-26}*1.06*10^{-10})^{1/2}\\K_{goal}=1.793*10^{-33}$

7 0

3 years ago

All the mixture are harmful for us. is this statement true? justify with two examples

Taya2010 [7]

Answer:

no.it is false.some are useful.like mixture of h2 and O 2 to form water.

3 0

3 years ago

Read 2 more answers

A sample of a uranium compound is found to be losing mass gradually. Explain what is happening to the sample.

irina [24]

Explanation:

Uranium have an unstable nuclei , hence it is a radioactive element , and radioactive element can undergo radioactive decay like the alpha decay , beta decay .

Radioactive decay is a spontaneous breakdown of the atomic nucleus which , results in the release of energy along with radioactive particles , like alpha , beta , gamma etc .

Hence ,

The mass is lost from a sample of uranium .

3 0

4 years ago