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Olin [163]
3 years ago
7

How do I calculate speed, velocity, and acceleration? I need the formulas too

Physics
1 answer:
vodomira [7]3 years ago
5 0
Speed is the secular unit, which means it only measures "how fast it goes."
speed= \frac{distance}{time}
Velocity is a victory unit, which means it measures "both how fast it goes AND the direction."
velocity= displacement/time
Acceleration is the change of velocity over time. 
acceleration =  \frac{change in velocity}{time}
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The diagram represents forces acting on a block that accelerates 6.0m/s/s on a
Ainat [17]

Answer: y=mx+b

Explanation:

because i say so

6 0
3 years ago
What happens to the sum of the ball's kinetic energy and potential energy as the ball rolls from point A to point E? Assume ther
sesenic [268]

Answer:

C. The sum remains the same.

Explanation:

The sum of the kinetic and potential energy remains the same as the all rolls from point A to E.

We know this based on the law of conservation of energy that is in play within the system.

The law of conservation of energy states that "energy is neither created nor destroyed within a system but transformed from one form to another".

  • At the top of the potential energy is maximum
  • As the ball rolls down, the potential energy is converted to kinetic energy.
  • Potential energy is due to the position of a body
  • Kinetic energy is due to the the motion of the body
7 0
3 years ago
A laser beam strikes a plane's surface with an angle of52.
Vadim26 [7]

Answer:

Angle between incident ray and reflected ray will be 104°

Explanation:

We have given angle of incidence = 52 °

From law of reflection angle of incidence will be equal to angle of reflection

So angle of reflection will be also 52°

We have to find the angle between incident ray and reflected ray

As the incidence angle and reflected angle both is from normal of the surface and opposite to each other

So angle between incident ray and reflected ray will be 52°+52° = 104°

7 0
4 years ago
When this current is closed which way does the current flow
Anastaziya [24]
Well, Godess, that's not a simple question, and it doesn't have
a simple answer.

When the switch is closed . . .

"Conventional current" flows out of the ' + ' of the battery, through R₁ ,
then through R₂ , then through R₃ .  It piles up on the right-hand side of
the capacitor (C).  It repels the ' + ' charges on the left side of 'C', and
those flow into the ' - ' side of the battery.  So the flow of current through
this series circuit is completely clockwise, around toward the right. 

That's the way the first experimenters pictured it, that's the way we still
handle it on paper, and that's the way our ammeters display it.

BUT . . .

About 100 years after we thought that we completely understand electricity,
we discovered that the little tiny things that really move through a wire, and
really carry the electric charge, are the electrons, and they carry NEGATIVE
charge.  This turned our whole picture upside down.

But we never changed the picture !  We still do all of our work in terms of
'conventional current'.  But the PHYSICAL current ... the actual motion of
charge in the wire ... is all exactly the other way around.

In your drawing ... When the switch is closed, electrons flow out of the 
' - ' terminal on the bottom of the battery, and pile up on the left plate of
the 'C'.  They repel electrons off of the right-side of 'C', and those then
flow through R₃ , then through R₂ , then through R₁ , and finally into the
' + ' terminal on top of the battery.

Those are the directions of 'conventional' current and 'physical' current
in all circuits.

In the circuit of YOUR picture that you attached, there's more to the story:

Battery current can't flow through a capacitor.  Current flows only until
charges are piled up on the two sides of 'C' facing each other, and then
it stops.

Wait a few seconds after you close the switch in the picture, and there is
no longer any current in the loop.

To be very specific and technical about it . . .

-- The instant you close the switch, the current is

       (battery voltage) / (R₁ + R₂ + R₃)        amperes

but it immediately starts to decrease.

--  Every  (C)/((R₁ + R₂ + R₃)  seconds after that, the current is

                  e⁻¹  =  about  36.8 %

less than it was that same amount of time ago.

Now, are you glad you asked ?
4 0
3 years ago
If a shuttle is orbiting a planet at a distance of 40 miles from the center of the planet, and is traveling at a rate of 500 mil
lawyer [7]

Answer:

Time taken, t = 30.15 minutes

Explanation:

It is given that,

Distance from the center of planet, r = 40 miles

Speed of the shuttle, v = 500 miles per hour

Let t is the time taken by it to complete  one full orbit. The displacement of the shuttle is,

d=2\pi r

d=2\pi \times 40

d = 251.32 miles

Now time can be calculated using the expression for the velocity as :

v=\dfrac{d}{t}

t=\dfrac{d}{v}

t=\dfrac{251.32\ miles}{500\ miles\ per\ hour}

t = 0.50264 hours

or

t = 30.15 minutes

So, the shuttle will take 30.15 minutes to complete one full orbit. Hence, this is the required solution.

7 0
3 years ago
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