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Olin [163]
3 years ago
7

How do I calculate speed, velocity, and acceleration? I need the formulas too

Physics
1 answer:
vodomira [7]3 years ago
5 0
Speed is the secular unit, which means it only measures "how fast it goes."
speed= \frac{distance}{time}
Velocity is a victory unit, which means it measures "both how fast it goes AND the direction."
velocity= displacement/time
Acceleration is the change of velocity over time. 
acceleration =  \frac{change in velocity}{time}
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The Electric Field 9.0m from a +25μC charge is 
salantis [7]

The electric field intensity generated by a single point charge is given by

E(r)=k\frac{q}{r^2}

where

k is the Coulomb's constant

q is the charge

r is the distance from the charge


In this problem, the charge is q=25 \mu C=25 \cdot 10^{-6} C and we are asked to calculate the field at distance r=9.0 m, so the electric field is

E(9.0 m)=(8.99 \cdot 10^9 Nm^2C^{-2})\frac{25 \cdot 10^{-6} C}{(9 m)^2}=2775 V/m

5 0
3 years ago
A 500 kg crate is lifted by a crane and accelerated upward at 2 m/s/s. What is the tension force in the cable pulling up on the
Likurg_2 [28]
Answer = 1000N
F = ma
M = 500kg
a= 2 m/s/s
Solve for F
6 0
3 years ago
Discuss Joule-Thompson effect with relevant examples and formulae.
Delicious77 [7]

Answer:

\mu _j=\dfrac{1}{C_p}\left [T\left(\frac{\partial v}{\partial T}\right)_p-v\right]dp

Explanation:

Joule -Thompson effect

 Throttling phenomenon is called Joule -Thompson effect.We know that throttling is a process in which pressure energy will convert in to thermal energy.

Generally in throttling exit pressure is low as compare to inlet pressure but exit temperature maybe more or less or maybe remains constant depending upon flow or fluid flow through passes.

Now lets take Steady flow process  

Let

 P_1,T_1 Pressure and temperature at inlet and

 P_2,T_2 Pressure and temperature at exit

We know that Joule -Thompson coefficient given as

\mu _j=\left(\frac{\partial T}{\partial p}\right)_h

Now from T-ds equation

dh=Tds=vdp

So

Tds=C_pdt-\left [T\left(\frac{\partial v}{\partial T}\right)_p\right]dp

⇒dh=C_pdt-\left [T\left(\frac{\partial v}{\partial T}\right)_p-v\right]dp

So Joule -Thompson coefficient

\mu _j=\dfrac{1}{C_p}\left [T\left(\frac{\partial v}{\partial T}\right)_p-v\right]dp

This is Joule -Thompson coefficient for all gas (real or ideal gas)

We know that for Ideal gas Pv=mRT

\dfrac{\partial v}{\partial T}=\dfrac{v}{T}

So by putting the values in

\mu _j=\dfrac{1}{C_p}\left [T\left(\frac{\partial v}{\partial T}\right)_p-v\right]dp

\mu _j=0 For ideal gas.

6 0
3 years ago
HELP ASAP!!!
S_A_V [24]
Hi there,

Burning fossil fuel should be a cause. Using aerosols also would be a cause.

Smog is an effect of air pollution. As well as acid rain, also I believe that loss of the ozone layer should be an effect of air pollution. I believe that volcano eruptions should be an cause of air pollution

I believe that smog reducing filters should be in the prevention box, as well for using electric cars.
5 0
4 years ago
Read 2 more answers
How does evaporation happen on a stove<br> (dont mind the subject btw)
Shtirlitz [24]

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

Answer: Evaporation happens by heat being transferred to the pot, then the pot transfering the heat to the water, which caused the water to vibrate more, eventually turning it into water vapor, which is how evaporation happens on the stove.

Explanation:

I hope this helped!

<!> Brainliest is appreciated! <!>

- Zack Slocum

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

3 0
3 years ago
Read 2 more answers
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