Answer:=6x2+5x + −4/15
Step-by-step explanation:Let's simplify step-by-step.
8x2−3x+13−(2x2−8x+3/5)
Distribute the Negative Sign:
=8x2−3x+13+−1(2x2−8x+3/5)
=8x2+−3x+13+−1(2x2)+−1(−8x)+−1(3/5)
=8x2+−3x+13+−2x2+8x+−3/5
Combine Like Terms:
=8x2+−3x+1/3+−2x2+8x+−3/5
=(8x2+−2x2)+(−3x+8x)+(1/3+−3/5)
=6x2+5x+−4/15
1. upwards
2. minimum -5
3. domain : xER range: y > -5
4) 2x^2 + 4x - 3
Answer:
t = 1 s
Step-by-step explanation:
The function models the height of the ball after t seconds is given by :

We need to find how many seconds does it take for the ball to reach its maximum height.
For maximum height put dh/dt = 0

So,
32-32t = 0
t = 1
So, it will take 1 second to reach its maximum height.