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mafiozo [28]
3 years ago
9

An object beginning with a negative velocity but undergoing a positive acceleration

Physics
1 answer:
RSB [31]3 years ago
5 0
The object’s velocity becomes less negative, then becomes zero, and finally becomes positive.
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Please help! Find the time. 8 POINTS!!
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Answer:

Time = 4.1 s

Explanation:

Momentum = mv = (12000)(4.25) = 51000 kg m/s

Momentum = Impulse (mv = ft) so

51000 = (9200)t

t = (51000)/(9200) = 5.54 seconds

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51000 = (12500)t

t = (51000)/(12500) = 4.08

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3 years ago
A child's top is held in place upright on a frictionless surface. The axle has a radius of ????=3.21 mm . Two strings are wrappe
tekilochka [14]

Answer:

Angular momentum, L=6.47\times 10^{-3}\ m

Explanation:

It is given that,

Radius of the axle, r=3.21\ mm=3.21\times 10^{-3}\ m

Tension acting on the top, T = 3.15 N

Time taken by the string to unwind, t = 0.32 s

We know that the rate of change of angular momentum is equal to the torque acting on the torque. The relation is given by :

\tau=\dfrac{dL}{dt}

Torque acting on the top is given by :

\tau=F\times r

Here, F is the tension acting on it. Torque acting on the top is given by :

\tau=2F\times r

2T\times r=\dfrac{L}{t}

L=2T\times r \times t

L=2\times 3.15\times 3.21\times 10^{-3}\times 0.32

L=6.47\times 10^{-3}\ m

So, the angular momentum acquired by the top is 6.47\times 10^{-3}\ m. Hence, this is the required solution.

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