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4 years ago

Which one of the following statements is not a characteristic of a plane mirror?

Physics

1 answer:

OleMash [197]4 years ago

4 0

Answer:

C) false. The image is formed by the prolongation of the rays, so it is VIRTUAL

Explanation:

Let's review each of the statements

A) True. The image is the same size as the object in a flat mirror, m = 1

B) True. The rays are not inverted, so the right images

C) false. The image is formed by the prolongation of the rays, so it is VIRTUAL

D) True. Flat mirrors reverse left and right

E) True. When using trigonometry the angles are equal, therefore two triangles formed have the same leg, and the distance to the object and the image are equal

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Which of the following describes an air mass with the symbol c t?

natali 33 [55]

The cT is short for continental tropical. It originates over the Mexican Plateau region and desert SW. It is a warm air mass over a continent. It is hot and very dry because of where it formed. Hope these facts about continental tropical air masses helped you!

8 0

3 years ago

The process by which pieces of rock get dropped off by wind, water or ice is called:___________

romanna [79]

Erosion - The process in which water, ice, wind, or gravity moves pieces of rock or soil

3 0

3 years ago

Read 2 more answers

A wire 95.0 mm long is bent in a right angle such that the wire starts at the origin and goes in a straight line to x = 40.0 mm

qaws [65]

Answer:

0.1040512455 N

$36.03^{\circ}\ or\ 323.97^{\circ}in\ CCW\ direction$

0.05925 N

$29.74^{\circ}\ or\ 330.26^{\circ}in\ CCW\ direction$

Explanation:

I = Current

B = Magnetic field

Separation between end points is

$l=\sqrt{40^2+55^2}\\\Rightarrow l=68.00735\ mm$

Effective force is given by

$F=IlB\\\Rightarrow F=5.1\times 68.00735\times 10^{-3}\times 0.3\\\Rightarrow F=0.1040512455\ N$

The force is 0.1040512455 N

$tan\theta=\dfrac{55}{40}\\\Rightarrow \theta=tan^{-1}\dfrac{55}{40}\\\Rightarrow \theta=53.97^{\circ}$

The angle the force makes is given by

$\alpha=\theta-90\\\Rightarrow \alpha=53.97-90\\\Rightarrow \alpha=-36.03^{\circ}\ or\ 323.97^{\circ}in\ CCW\ direction$

The direction is $36.03^{\circ}\ or\ 323.97^{\circ}in\ CCW\ direction$

$F=IlB\\\Rightarrow F=4.9\times \sqrt{20^2+35^2}\times 10^{-3}\times 0.3\\\Rightarrow F=0.05925\ N$

The force is 0.05925 N

$tan\theta=\dfrac{35}{20}\\\Rightarrow \theta=tan^{-1}\dfrac{35}{20}\\\Rightarrow \theta=60.26^{\circ}$

$\alpha=\theta-90\\\Rightarrow \alpha=60.26-90\\\Rightarrow \alpha=-29.74^{\circ}\ or\ 330.26^{\circ}in\ CCW\ direction$

The direction is $29.74^{\circ}\ or\ 330.26^{\circ}in\ CCW\ direction$

4 0

3 years ago

An ice block measuring 5cm by 5cm by 5cm has a desity of 5g/cm3. What is the mass of the ice block?

Svetradugi [14.3K]

Density = (mass) / (volume)

Volume of your block = (5cm x 5cm x 5cm) = 125 cm³

5 gm/cm³ = (mass) / (125 cm³)

Multiply each side by (125 cm³): Mass = 625 gm

Note:
I don't know what kind of frozen substance you're working with,
but maybe you ought to be careful handling it ... I know that's
not water ice you have there. The density of water ice is not
5 gm/cm³. In fact, it's a little less than 1 gm/cm³. That's why
the ice floats in your soda.

4 0

3 years ago

Read 2 more answers

ustapha Jones is speeding on the interstate in his Ferrari at 231km/hr when he passes a police car at rest . If the cop accelera

Lena [83]

Answer:

461 km/h

Explanation:

In order to solve this problem we must first sketch a drawing of what the situation looks like so we can better visualize it. (See attached picture).

We have two situations there, the first one is Mustapha's car that is traveling at a constant speed of 231km/hr.

The second situation is the police that is accelerating from rest until he reaches Mustapha. (We are going to suppose the acceleration is constant and that he will not stop accelerating until he reaches Mustapha). He has an acceleration of 15m/ $s^{2}$ .

We want to find what the final velocity of the police is at the time he reaches Mustapha. From this we can imply that the displacement x will be the same for both particles.

So let's model the first situation.

The displacement of Mustapha can be found by using the following equation:

$V_{M}=\frac{x}{t}$

when solving the equation for the displacement x we get that it will be:

$x=V_{M}t$

Now let's model the displacement of the cop. Since the cop has a constant acceleration, we can model his displacement with the following formula.

$x=V_{0}t+\frac{1}{2}at^{2}$

Since the initial velocity of the cop is zero, we can get rid of that part of the equation leaving us with:

$x=\frac{1}{2}at^{2}$

We can now set both equations equal to each other so we get:

$\frac{1}{2}at^{2}=V_{M}t$

When solving this for t, we get that:

$t=\frac{2V_{M}}{a}$ (let's call this equation 1)

Now, we know the cop has constant acceleration, so we can model it with the following formula too:

$a=\frac{V_{f}-V_{0}}{t}$

since the initial velocity of the cop is zero, we can get rid of that here too, so we get the following formula:

$a=\frac{V_{f}}{t}$

when solving for the final velocity, we get that:

$V_{f}=at$ (let's call this equation 2)

when substituting equation 1 into equation 2 we get:

$V_{f}=a(\frac{2V_{M}}{a})$

we can now cancel a leaving us with:

$V_{f}=2V_{M}$

This tells us that the final velocity of the cop will not depend on his acceleration. (This is only if the acceleration is constant all the time) So we get that the final velocity of the cop is:

$V_{f}=2(231km/hr)$

$V_{f}=461km/hr$

which is our answer.

8 0

3 years ago