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BigorU [14]
4 years ago
6

Which one of the following statements is not a characteristic of a plane mirror?

Physics
1 answer:
OleMash [197]4 years ago
4 0

Answer:

C) false. The image is formed by the prolongation of the rays, so it is VIRTUAL

Explanation:

Let's review each of the statements

A) True. The image is the same size as the object in a flat mirror, m = 1

B) True. The rays are not inverted, so the right images

C) false. The image is formed by the prolongation of the rays, so it is VIRTUAL

D) True. Flat mirrors reverse left and right

E) True. When using trigonometry the angles are equal, therefore two triangles formed have the same leg, and the distance to the object and the image are equal

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Little Susie is enjoying a nice spherical lollipop. She sucks the lollipop in such away that the circumference decreases by 1 ce
Brums [2.3K]

Answer:

-50 cm^3/min

Explanation:

The volume of the lollipop is given by

V=\frac{4}{3}\pi r^3

where r is the radius in centimeters.

To find how fast the volume changes, we need to find the rate of change of the volume, which is given by its derivative with respect to time:

\frac{dV}{dt}=4\pi r^2 \frac{dr}{dt} (1)

where

dr/dt is the rate of change of the radius

We know that the circumference is

C=2\pi r

and it decreases by 1 cm per minute, so

\frac{dC}{dt}=2\pi \frac{dr}{dt}=-1 (cm/min)

from which we find dr/dt:

\frac{dr}{dt}=-\frac{1}{2\pi}

Substituting into (1),

\frac{dV}{dt}=4\pi r^2 \frac{1}{2\pi}=-2r^2  (cm^3/min)

And substituting r = 5, we find the rate of change of the volume when the radius is 5 cm:

\frac{dV}{dt}=-2(5)^2=-50 (cm^3/min)

8 0
3 years ago
If an object in space is giving off a frequency of 10^13 wavelength of 10^-6 what will scientist be looking for?
aev [14]

Answer:

The scientist will be looking for the velocity of the wave in air which is equivalent to 10^7m/s

Explanation:

If an object in space is giving off a frequency of 10^13Hz and wavelength of 10^-6m then the scientist will be looking for the velocity of the object in air.

The relationship between the frequency (f) of a wave, the wavelength (¶) and the velocity of the wave in air(v) is expressed as;

v = f¶

Given f = 10^13Hz and ¶ = 10^-6m,

v = 10¹³ × 10^-6

v = 10^7 m/s

The value of the velocity of the object in space that the scientist will be looking for is 10^7m/s

5 0
4 years ago
Florida law applies the same protections given to pedestrians to any person riding or leading an animal upon a roadway
dmitriy555 [2]

Answer:

True

Explanation:

The Florida law states that a person driving an animal-drawn vehicle has the same protections that are applicable to a person driving a vehicle and the protections that are applicable to pedestrians also apply to a person riding or leading an animal upon a roadway or the shoulder of it. According to this, the answer is that the statement is true.

5 0
3 years ago
Lucy took 3 hours to cover 2/3 of a journey. She covered the
Grace [21]

Deleted this answer, sorry for any inconveniences that it may have caused.

7 0
3 years ago
Calculate how much work you need to move a 280 N shed to a platform 5 m above.
castortr0y [4]
Work is done when a motion resulted from the force being done by an object. The amount of work done is calculated by multiplying the force applied and the distance traveled. It is calculated as follows:

Work = Force x distance = 280 N x 5 m  =  1400 J.
6 0
3 years ago
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