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Aleks [24]
3 years ago
13

How many liters of water are needed to make a 4.00 M solution using 75.0

Chemistry
1 answer:
timurjin [86]3 years ago
7 0

Answer:

0.22L

Explanation:

Given parameters:

Concentration of solution  = 4.00M

Mass of lithium Bromide  = 75g

Unknown:

Volume of water  = ?

Solution:

Concentration in terms of the molarity is the number of moles of solute in a solution.

   Molarity  = \frac{number of moles }{volume of solution}

let us find the number of moles first;

Number of moles  = \frac{mass}{molar mass}  

  Molar mass of LiBr =  7 + 80  = 78g/mol

                                 number of moles  = \frac{75}{78}

                                 number of moles  = 0.96moles

Volume of water  = \frac{number of moles }{molarity}   = 0.96/4 = 0.22L

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A gas is confined in a 0.3m diameter cylinder by a piston, on which rests a weight. The mass of the piston is 85 kg. The local a
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Explanation:

Force applied on the gas will be as follows.

                   F_{gas} = F_{atm} + (m + M) g

As,   F = pressure × area. Hence, calculate the forces as follows.

                  F_{gas} = pressure × area

                         = 1.4 \times 10^{5} Pa \times \pi \times (\frac{0.3}{2})^{2}

                          = 1.979 \times 10^{4} N

                  F_{atm} = pressure × area

                            = 1.0133 \times 10^{5} \times \pi \times (\frac{0.3}{2})^{2}

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      F_{gas} - F_{atm} = 5.47 \times 10^{3} N

Substituting the calculated values into the above formula as follows.

                F_{gas} = F_{atm} + (m + M) g

              F_{gas} - F_{atm} = (m + M) g

              5.47 \times 10^{3} N = (m + 85) \times 9.8    

              5.47 \times 10^{3} N = 9.8m + 833

                               m = 472.76 kg

Thus, we can conclude that the mass is 472.76 kg.  

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4 years ago
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