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3 years ago

How many liters of water are needed to make a 4.00 M solution using 75.0

Chemistry

1 answer:

timurjin [86]3 years ago

7 0

Answer:

0.22L

Explanation:

Given parameters:

Concentration of solution = 4.00M

Mass of lithium Bromide = 75g

Unknown:

Volume of water = ?

Solution:

Concentration in terms of the molarity is the number of moles of solute in a solution.

Molarity = $\frac{number of moles }{volume of solution}$

let us find the number of moles first;

Number of moles = $\frac{mass}{molar mass}$

Molar mass of LiBr = 7 + 80 = 78g/mol

number of moles = $\frac{75}{78}$

number of moles = 0.96moles

Volume of water = $\frac{number of moles }{molarity}$ = 0.96/4 = 0.22L

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QUËSTIONS :- what are the difference between ionic bond and covalent bond?

IONIC BONDS :- THEY R BONDS WHICH R FORMED DUE TO THE COMPLETE TRANSFER OF ELECTRONS BETWEEN TWO ATOMS

COVALENT BONDS :- THEY R THE BONDS WHICH R FORMED DUE TO INCOMPLETE TRANSFER OF ELECTRONS BETWEEN TWO ATOMS

IONIC BONDS R MORE STRONGER.

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3 years ago

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How can you recognize an alcohol?

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Answer:

O D. It has an -OH group attached to the end of the molecule.

Explanation:

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5 0

3 years ago

36. Dimensional Analysis: A useful way to convert units using multiplication & division *Always start with what you are give

ollegr [7]

Answer:

A) 7.9 x 10⁶ inches

B) 1004 g

C) 2.8 x 10³ inches/ min

D) 1.2 x 10⁻⁴ mm

Explanation:

A) Since 39.37 inches = 1 m, you can convert meters to inches by multiplying by the conversion factor (39.37 inches / 1 m).

Notice that if 39.37 inches = 1 m then 39.37 inches / 1 m = 1. That means that when you multiply by a conversion factor, you are only changing units since it is the same as multiplying by 1 :

2.0 x 10⁵ m * (39.37 inches / 1 m) = 7.9 x 10⁶ inches

B) Conversion factors : (2.205 pounds / 1 kg) and (453.59 g / 1 pound), because 2.205 pounds = 1 kg and 1 pound = 453.59 g. Then:

1.004 kg * ( 2.205 pounds / 1 kg) * ( 453.59 g / 1 pound) = 1004 g

C) Conversion factor: (39.37 inches / 1 m) and (60 s / 1 min)

1.2 m/s * (39.37 inches / 1 m) * ( 60 s / 1 min) = 2.8 x 10³ inches/ min

D)Converison factor ( 1 mm / 1 x 10⁶ nm):

120 nm (1 mm / 1 x 10⁶ nm) = 1.2 x 10⁻⁴ mm

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3 years ago

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A 35.161 mg sample of a chemical known to contain only carbon, hydrogen, sulfur, and oxygen is put into a combustion analysis ap

xxMikexx [17]

Answer:

The empirical formulae is C6H12S02

Explanation:

1. First we need to obtain the mass of each element in the sample and compound formed

Carbon = (62.637 mg * 12.011 g/mol / 44.009 g/mol) = 17.094 mg of Carbon

Hydrogen = ( 25.641 mg * (2 *1..008 g/mol) / 18.015 g/mol) = 2.869 mg of Hydrogen

Sulphur = (13.54 mg * 32.066 g/mol / 64.066 g/mol) = 6.777 mg of Sulphur

2. Next is to determine the percentage composition. Here we divide the respective mass by the mass of the sample

Carbon = 17.094 / 35.161 * 100 = 48.62 %

Hydrogen = 2.869/ 35.161 *100 = 8.16 %

Sulphur = 6.777/ 31.321 *100 = 21.64 %

Oxygen = (100 - (48.62 + 8.16 + 21.64)) = 21.58 %

3. Next is to divide the mass assuming there are 100 mg by the respective atomic masses to obtain the number of moles

Carbon = 48.62 / 12.011 = 4.048 mol

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Sulphur = 21.64 / 32.066 = 0.675 mol

Oxygen = 21.58 / 16.000 = 1.348 mol

Next is to divide by the smallest value

Carbon = 4.048/ 0.675 =5.997 = 6

Hydrogen = 8.095 / 0.675 =11.993 =12

Sulphur = 0.675/ 0.675 = 1

Oxygen = 1.348 / 0.675 = 1.997 = 2

So therefore the empirical formulae of the sample is C6H12SO2

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3 years ago

What is the molarity of a solution made by dissolving 18.9g of ammonium nitrate in enough water to make 855 ml of solution?

Leya [2.2K]

Answer is: the molarity of a solution is 0.276 M.<span>

V(solution) = 855 mL </span>÷ 1000 mL/L.
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M(NH₄NO₃) = 80.04 g/mol; molar mass of ammonium nitrate.
n(NH₄NO₃) = m(NH₄NO₃) ÷ M(NH₄NO₃).
n(NH₄NO₃) = 18.9 g ÷ 80.04 g/mol.
n(NH₄NO₃) = 0.236 mol; amount of substance.
c(NH₄NO₃) = n(NH₄NO₃) ÷ V(solution).
c(NH₄NO₃) = 0.236 mol ÷ 0.855 L.
c(NH₄NO₃) = 0.276 mol/L; molarity of ammonium nitrate.

7 0

3 years ago