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suter [353]
3 years ago
5

During an experiment a thermometer was placed in a beaker containing hydrogen peroxide. The following observations were recorded

when yeast granules were added to hydrogen peroxide. Observation 1: Fizzing and bubbling took place. Observation 2: The temperature began to rise. Based on the observation, justify the type of change (physical or chemical) that took place.
Chemistry
2 answers:
patriot [66]3 years ago
4 0

Answer:

Chemical

Explanation:

The form is changing, you cannot get those bubbles back.

Rudiy273 years ago
3 0

Answer:

Chemical

Explanation:

The change was chemical, because it can no longer be returned to the original form. You cannot get back the bubbles or fizz from the air.

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a 58.215 g sample of a pure metal is brought to 99.0c and added o 41.202 g of water at 21.5c in a calorimeter. if the metal and
Vinil7 [7]

Answer:

The answer to your question is a)   C = 0.056 cal/g°C     b) 107.8 g/mol

Explanation:

I included a picture of the problem because it says that it has inappropriate words or links

4 0
3 years ago
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Explain why most volcanoes and earthquakes occur along boundaries between tectonic plates.
rodikova [14]
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3 0
3 years ago
Sugars are polar substances. Which action would make sugar more soluble in water?
Helen [10]

Answer the correct answer for the question is option a Increase in temperature of water.

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5 0
4 years ago
A) 2Fe(s) + O2(g) =>
TiliK225 [7]

Answer:  -22.2 kJ

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps. SGDSDGSDGSDGgsg

According to Hess’s law, the chemical equation can be treated as algebraic expressions and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

(1)  2Fe(s)+O_2(g)\rightarrow 2FeO(s)  \Delta H_1=-544.0kJ

(2)  4Fe(s)+O_2(g)\rightarrow 2Fe_2O_3(s)  \Delta H_2=-1648.4kJ

(3)  Fe_3O_4(s)\rightarrow 3Fe(s)+2O_2(g)  \Delta H=+1118.4kJ

Reversing 1 ,2 and 3 and halving 1 and 2 and then adding we get net equation:

(4) Fe_2O_3(s)+FeO(s)\rightarrow Fe_3O_4(s)  \Delta H_4=?

\Delta H_4=\frac{-\Delta H_1}{2}+\frac{-\Delta H_2}{2}+(-\Delta H_3)=\frac{544.0}{2}+\frac{1648.4}{2}+(-1118.4)=-22.2kJ

Therefore, the heat of reaction, ΔH, for the reaction is -22.2 kJ

6 0
3 years ago
Why does scientists use atomic watch?​
Maru [420]

Answer:

atomic watch

Explanation:

it is used for the measurement of time.

6 0
2 years ago
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