Question

HCl(aq)+NaOH(aq)→NaCl(aq)+H2O(l)

Answer 1

Answer:

0.036 g

Explanation:

0.036 g of water should be produced.

From the equation of reaction, 1 mole of HCl requires 1 mole of NaOH in order to produce 1 mole of H2O.

20 mL of 0.10 M HCl contains 20/1000 x 0.10 = 0.002 moles of HCl

46 grams of NaOH contains 46/40 = 1.15 moles of NaOH

It thus means that the HCl is a limiting reagent in the reaction.

From the equation:

1 mole  HCl will produce 1 mole of H2O.

0.002 HCl with therefore produce 0.002 x 1/1 = 0.002 mole of H2O

Mass of water produced = mole x molar mass

    0.002 x 18 = 0.036 g.

Hence, 0.036 g of water would be produced.