Answer:
0.036 g
Explanation:
<em>0.036 g of water should be produced.</em>
From the equation of reaction, 1 mole of HCl requires 1 mole of NaOH in order to produce 1 mole of H2O.
20 mL of 0.10 M HCl contains 20/1000 x 0.10 = 0.002 moles of HCl
46 grams of NaOH contains 46/40 = 1.15 moles of NaOH
<em>It thus means that the HCl is a limiting reagent in the reaction.</em>
From the equation:
1 mole HCl will produce 1 mole of H2O.
0.002 HCl with therefore produce 0.002 x 1/1 = 0.002 mole of H2O
<em>Mass of water produced = mole x molar mass</em>
0.002 x 18 = 0.036 g.
Hence, 0.036 g of water would be produced.
