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Anna [14]
3 years ago
5

A 50.6 grams sample of magnesium hydroxide (Mg(OH)2) is reacted with 45.0 grams of hydrochloric acid (HCl). What is the theoreti

cal yield of magnesium chloride (MgCl2)? Mg(OH)2 + 2 HCl MgCl2 + 2 H2O 29.3 grams
Chemistry
2 answers:
boyakko [2]3 years ago
7 0
The answer is C, 58.6
il63 [147K]3 years ago
7 0

<u>Answer:</u> The theoretical yield of magnesium chloride is 58.6 g

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For magnesium hydroxide:</u>

Given mass of magnesium hydroxide = 50.6 g

Molar mass of magnesium hydroxide = 58.32 g/mol

Putting values in equation 1, we get:

\text{Moles of magnesium hydroxide}=\frac{50.6g}{58.32g/mol}=0.87mol

  • <u>For HCl:</u>

Given mass of HCl = 45.0 g

Molar mass of HCl = 36.5 g/mol

Putting values in equation 1, we get:

\text{Moles of HCl}=\frac{45.0g}{36.5g/mol}=1.23mol

  • The chemical equation for the reaction of magnesium hydroxide and HCl follows:

Mg(OH)_2+2HCl\rightarrow MgCl_2+2H_2O

By Stoichiometry of the reaction:

2 moles of HCl reacts with 1 mole of magnesium hydroxide

So, 1.23 moles of HCl will react with = \frac{1}{2}\times 1.23=0.615mol of magnesium hydroxide

As, given amount of magnesium hydroxide is more than the required amount. So, it is considered as an excess reagent.

Thus, HCl is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of HCl produces 1 mole of magnesium chloride

So, 1.23 moles of HCl will produce = \frac{1}{2}\times 1.23=0.615mol of magnesium chloride

  • To calculate the theoretical yield of magnesium chloride we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of magnesium chloride = 95.21 g/mol

Moles of magnesium chloride = 0.615 moles

Putting values in above equation, we get:

0.615mol=\frac{\text{Mass of magnesium chloride}}{95.21g/mol}\\\\\text{Mass of magnesium chloride}=(0.615mol\times 95.21g/mol)=58.6g

Hence, the theoretical yield of magnesium chloride is 58.6 g

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