I believe they’re both true.
Answer:
1.829 meters is the answer
Explanation:
Answer:
3.81 g Pb
Explanation:
When a lead acid car battery is recharged, the following half-reactions take place:
Cathode: PbSO₄(s) + H⁺ (aq) + 2e⁻ → Pb(s) + HSO₄⁻(aq)
Anode: PbSO₄(s) + 2 H₂O(l) → PbO₂(s) + HSO₄⁻(aq) + 3H⁺ (aq) + 2e⁻
We can establish the following relations:
- 1 A = 1 c/s
- 1 mole of Pb(s) is deposited when 2 moles of e⁻ circulate.
- The molar mass of Pb is 207.2 g/mol
- 1 mol of e⁻ has a charge of 96468 c (Faraday's constant)
Suppose a current of 96.0A is fed into a car battery for 37.0 seconds. The mass of lead deposited is:
![37.0s.\frac{96.0c}{s} .\frac{1mole^{-} }{96468c} .\frac{1molPb}{2mole^{-} } .\frac{207.2gPb}{1molPb} =3.81gPb](https://tex.z-dn.net/?f=37.0s.%5Cfrac%7B96.0c%7D%7Bs%7D%20.%5Cfrac%7B1mole%5E%7B-%7D%20%7D%7B96468c%7D%20.%5Cfrac%7B1molPb%7D%7B2mole%5E%7B-%7D%20%7D%20.%5Cfrac%7B207.2gPb%7D%7B1molPb%7D%20%3D3.81gPb)
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