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2 years ago

Can I get some help

Mathematics

1 answer:

ra1l [238]2 years ago

5 0

Answer:

The answer to your question is below

Step-by-step explanation:

The answers for 1, 3 and 4 are given in decimals and roots.

1) $\sqrt{2^{2} - 4(3)(-6)}$

$\sqrt{4 + 72}$

$\sqrt{76}$

$2\sqrt{19} = 8.71$

2) $\sqrt{1^{2} -4(1)(-6)}$

$\sqrt{1 + 24}$

$\sqrt{25}$

3) $\sqrt{1^{2} - 4(1)(-11)}$

$\sqrt{1 + 44}$

$\sqrt{45}$

$3\sqrt{5} = 6.7$

4) $\sqrt{8^{2} -4(5)(2)}$

$\sqrt{64 - 40}$

$\sqrt{24}$

$2\sqrt{6} = 4.89$

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Assume a simple random sample of 10 BMIs with a standard deviation of 1.186 is selected from a normally distributed population o

kirza4 [7]

Answer:

a) H0: $\sigma = 1.34$

H1: $\sigma \neq 1.34$

b) $df = n-1= 10-1=9$

And the critical values with $\alpha/2=0.005$ on each tail are:

$\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589$

c) $t=(10-1) [\frac{1.186}{1.34}]^2 =7.05$

d) For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

Step-by-step explanation:

Information provided

n = 10 sample size

s= 1.186 the sample deviation

$\sigma_o =1.34$ the value that we want to test

$p_v$ represent the p value for the test

t represent the statistic (chi square test)

$\alpha=0.01$ significance level

Part a

On this case we want to test if the true deviation is 1,34 or no, so the system of hypothesis are:

H0: $\sigma = 1.34$

H1: $\sigma \neq 1.34$

The statistic is given by:

$t=(n-1) [\frac{s}{\sigma_o}]^2$

Part b

The degrees of freedom are given by:

$df = n-1= 10-1=9$

And the critical values with $\alpha/2=0.005$ on each tail are:

$\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589$

Part c

Replacing the info we got:

$t=(10-1) [\frac{1.186}{1.34}]^2 =7.05$

Part d

For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

5 0

2 years ago

Identify all the prime numbers within each range of numbers given below (inclusive): a. 4 to 11 and b.) 16 to 25

scZoUnD [109]

Answer:

A. 5, 7, 11; B: 17, 19, 23

Step-by-step explanation:

These are all the numbers that don't have common factors besides one and itself

5 star, thank, and brainliest if helpful!

8 0

3 years ago

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