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3 years ago

1. Material that is made of living cells and tissues is called________________. * please help

Physics

2 answers:

mihalych1998 [28]3 years ago

8 0

Answer:

organ

..........it may help you......

just olya [345]3 years ago

4 0

Answer:

DERMAL TISSUES

Explanation:

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If the price of gasoline at a particular station in Europe is 5 euros per liter. An American student in Europe is allowed to use

Mashcka [7]

Answer:

Number of gallons =2 gallon

Explanation:

given data:

rate of gasoline ineurope = 5 euro per liter

total money to buy gasoline = 40 euro

total gasoline an american can buy in europe $= \frac{40}{5}$

= 8 litres of gasoline

As given in the question 1 ltr is 1 quarts therefore

Total no. of quarts is 8 quarts

As from question 4 quarts is equal to one gallon, hence

Number of gallons $= \frac{8}{4} = 2 gallon$

5 0

3 years ago

Why does the density of a substance remain the same for different amounts of the substance

Novay_Z [31]

The molarity remains the same so the ratio does not change

5 0

3 years ago

Define energy and provide examples of potential and kinetic energy

In-s [12.5K]

Energy is the capacity for doing work..

Kinetic energy - Moving car

Potential energy - flowing water up the hill

6 0

2 years ago

A simple and common technique for accelerating electrons is shown in the figure, where there is a uniform electric field between

Sunny_sXe [5.5K]

Answer : $4.483\times 10^{15}\ m/s^2$ .

Explanation:

It is given that,

Electric field strength, $E=2.55\times 10^{4}\ N/C$

We know that,

Charge of electron, $q=1.6\times 10^{-19}\ C$

Mass of electron, $m=9.1\times 10^{-31}\ kg$

From the definition of electric field, $F=qE$ ...............(1)

According to Newton's second law, F = ma..........(2)

From equation (1) and (2)

$ma=qE$

$a=\dfrac{qE}{m}$

$a=\dfrac{1.6\times 10^{-19}\ C\times 2.55\times 10^{4}\ N/C }{9.1\times 10^{-31}\ kg}$

$a=0.4483\times 10^{16}\ m/s^2$

$a=4.483\times 10^{15}\ m/s^2$

So, the horizontal component of acceleration of an electron is $4.483\times 10^{15}\ m/s^2$ .

Hence, it is the required solution.

7 0

3 years ago

An apparatus like the one Cavendish used to ﬁnd G has large lead balls that are 5.2 kg in mass and small ones that are 0.046 kg.

Ber [7]

Answer:

The magnitude of gravitational force between two masses is $4.91\times 10^{-9}\ N$ .

Explanation:

Given that,

Mass of first lead ball, $m_1=5.2\ kg$

Mass of the other lead ball, $m_2=0.046\ kg$

The center of a large ball is separated by 0.057 m from the center of a small ball, r = 0.057 m

We need to find the magnitude of the gravitational force between the masses. It is given by the formula of the gravitational force. It is given by :

$F=G\dfrac{m_1m_2}{r^2}\\\\F=6.67259\times 10^{-11}\times \dfrac{5.2\times 0.046}{(0.057)^2}\\\\F=4.91\times 10^{-9}\ N$

So, the magnitude of gravitational force between two masses is $4.91\times 10^{-9}\ N$ . Hence, this is the required solution.

5 0

2 years ago