Answer: The answer is A. The company is trying to transfer intellectual capital to a knowledge management system
Answer:
percentage change in volume = 0.00285 %
Explanation:
given data
bulk modulus = 3.5 ×
N/m²
bulk stress =
N/m²
solution
we will apply here bulk modulus formula that is
bulk modulus =
...............1
put here value and we get
3.5 ×
=
solve it we get
bulk strain = 2.8571 ×
and
bulk strain =
so that percentage change in volume is = 2.8571 ×
× 100
percentage change in volume = 0.00285 %
Answer:
The answer is option
C . the JFET has a PN junction
Explanation:
Not only is option C in the question a dissimilarity between the MOSFET and the JFET we can go on with some more dissimilarities.
1.MOSFET stands for Metal Oxide Silicon Field Effect Transistor or Metal Oxide Semiconductor Field Effect Transistor.
(JFET) stands for junction gate field-effect transistor (JFET)
2. JFET is a three-terminal semiconductor device, whereas MOFET a four-terminal semiconductor device.
3. In terms of areas of application of JFETs are used in low noise applications while MOSFETs, are used for high noise applications
Answer:
h = 375 KW/m^2K
Explanation:
Given:
Thermo-couple distances: L_1 = 10 mm , L_2 = 20 mm
steel thermal conductivity k = 15 W / mK
Thermo-couple temperature measurements: T_1 = 50 C , T_2 = 40 C
Air Temp T_∞ = 100 C
Assuming there are no other energy sources, energy balance equation is:
E_in = E_out
q"_cond = q"_conv
Since, its a case 1-D steady state conduction, the total heat transfer rate can be found from Fourier's Law for surfaces 1 and 2
q"_cond = k * (T_1 - T_2) / (L_2 - L_1) = 15 * (50 - 40) / (0.02 - 0.01)
=15KW/m^2
Assuming SS is solid, temperature at the surface exposed to air will be 60 C since its gradient is linear in the case of conduction, and there are two temperatures given in the problem. Convection coefficient can be found from Newton's Law of cooling:
q"_conv = h * ( T_∞ - T_s ) ----> h = q"_conv / ( T_∞ - T_s )
h = 15000 W / (100 - 60 ) C = 375 KW/m^2K
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