Answer
given,
6 lanes divided highway 3 lanes in each direction
rolling terrain
lane width = 10'
shoulder on right = 5'
PHF = 0.9
shoulder on the left direction = 3'
peak hour volume = 3500 veh/hr
large truck = 7 %
tractor trailer = 3 %
speed = 55 mi/h
LOS is determined based on V p
10' lane weight ; f_{Lw}=6.6 mi/h
5' on right ; f_{Lc} = 0.4 mi/hr
3' on left ; no adjustment
3 lanes in each direction f n = 3 mi/h
= 0.877
= 1,555 veh/hr/lane
= (55 + 5) - 6.6 - 0.4 -3 -0
= 50 mi/h
level of service is D using speed flow curves and LOS for basic free moving of vehicle
Given data:
•) applied voltage = 15 V
•). Resistance = 1000 ohm
Required:
•). The magnitude of current= ?
•••••••••••••SOLUTION•••••••••••••
We can find the relation ship between current, voltage and resistance with the help of Ohms law.
According to ohms law;
V= IR.
Rearranging the above equation;
I= V/ R
Putt the values in the above equation; we get
I= 15V/ 1000ohm
I = 0.015 A( ampere)
••••••••••••••• CONCLUSION•••••••
The value of the current would be 0.15 ampere when Resistance is equal to 1000 and that of Voltage is equal to 15 V.
Answer:
The total tube surface area in m² required to achieve an air outlet temperature of 850 K is 192.3 m²
Explanation:
Here we have the heat Q given as follows;
Q = 15 × 1075 × (1100 - 
) = 10 × 1075 × (850 - 300) = 5912500 J
∴ 1100 - = 1100/3
= 733.33 K
Where
= Arithmetic mean temperature difference
= Inlet temperature of the gas = 1100 K
= Outlet temperature of the gas = 733.33 K
= Inlet temperature of the air = 300 K
= Outlet temperature of the air = 850 K
Hence, plugging in the values, we have;
Hence, from;
, we have
5912500 = 90 × A × 341.67
Hence, the total tube surface area in m² required to achieve an air outlet temperature of 850 K = 192.3 m².
