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Kisachek [45]
3 years ago
7

Witch answer represents a speed, of velocity A-35m/s B-35 m/s south C- 35 m/s east -35 m/a down

Physics
1 answer:
sladkih [1.3K]3 years ago
3 0

Answer:

A 35 m/s

Explanation:

Speed of any object is scalar quantity while velocity is a vector. The scalar quantity is represented only by magnitude it doesn't need direction.

Hence, option A is correct as all other options have direction as well.

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Describe the movement of particles at the melting point of a substance with temperature and energy.
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Answer:

As a substance reaches the melting point, the particles begin to move faster, causing the substance to become a liquid.

Explanation:

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2 years ago
Which option describes the direction of thermal energy transfer in Earth's
Montano1993 [528]

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Explanation:

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A geneticist looks through a microscope to determine the phenotype of a fruit fly. The microscope is set to an overall magnifica
guajiro [1.7K]

Answer:

f_{e} = 1.7 cm

Explanation:

The magnification of the compound microscope is given by the product of the magnification of each lens

        M = M₀ m_{e}

        M = - L/f₀  25/f_{e}

Where f₀ and f_{e} are the focal lengths of the lens and eyepiece, respectively, all values ​​in centimeters

In this exercise they give us the magnification (M = 400X), the focal length of the lens (f₀ = 0.6 cm), the distance of the tube (L = 16 cm), let's look for the focal length of the eyepiece (f_{e})

         f_{e} = - L / f₀ 25 / M

Let's calculate

        f_{e} = - 16 / 0.6 25 / (-400)

        f_{e} = 1.67 cm

The minus sign in the magnification is because the image is inverted.

          f_{e} = 1.7 cm

6 0
3 years ago
A planet orbits a sun in a clockwise elliptical orbit as shown in the diagram below
STatiana [176]

Answer:

Greatest gravitational energy is at "C".

The planet has to do work "against" the field to get to "C".

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3 0
3 years ago
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boyakko [2]

Answer:

Both objects have the same magnitude of momentum.

Explanation:

If an object of mass m is moving at a velocity of v, the momentum of that object would be m\, v.

The 100\; {\rm g} (0.1\; {\rm kg}) object is moving at a speed of 1\; {\rm m\cdot s^{-1}}. The magnitude of the momentum of this object would be 0.1\; {\rm kg} \times 1\; {\rm m\cdot s^{-1}} = 0.1\; {\rm kg \cdot m \cdot s^{-1}}.

Similarly, the momentum of the 1\; {\rm g} (10^{-3}\; {\rm kg}) object moving at a speed of 100\; {\rm m\cdot s^{-1}} would be 10^{-3}\; {\rm kg} \times 100\; {\rm m\cdot s^{-1}} = 0.1\; {\rm kg \cdot m \cdot s^{-1}}.

Hence, the magnitude of momentum is the same for the two objects.

7 0
2 years ago
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