Answer:
Explanation:
We shall represent each displacement in vector form .
i will represent east , j will represent north .
D₁ = 4.1 west = - 4.1 i
D₂ = 17.3 north = 17.3 j
D₃ = - 1.2 cos65.4 i + 1.2 sin65.4 j
= - .5 i + 1.09 j
Total displacement
= D₁ + D₂ + D₃
= - 4.1 i + 17.3 j - .5 i + 1.09 j
D = - 4.6 i + 18.39 j
magnitude of D
= √ ( 4.6² + 18.39² )
= √ (21.16 + 338.2 )
= √359.36
= 18.95 km .
Final displacement = 18.95 km .
Answer:
15 m/s
Explanation:
The Speed Of The Car Does Not Add To The Speed Of The Bullet
1). D. Combined Gas Law
3.) D. Pressure and temperature
4.) C. Boyles law
Answer:
The Force exerted on the student by crate will be 100 N.
Explanation:
As per the given Question student is trying to push the crate in right direction with the force of 100N.
And we know that, Newton's third law states that every action has equal and opposite reaction.
So from the Newton's 3rd law of motion it is very clear the student must be experiencing the same amount of force which he is applying.
Above their melting point, metals are liquids, and their atoms are randomly arranged and relatively free to move. However, when cooled below their melting point, metals rearrange to form ordered, crystalline structures.
