Answer: B) exactly the same as the initial momentum.
Explanation:
An inelastic collision occurs when the elements that collide remain together after the collision, and althogh the kinetic energy is not conserved because is transformed into other kinds of energy (thermal energy, for example), the linear momentum does.
This means the initial momentum before the collision will be equal to the final momentum after the collision:
Answer:
The base runner
Explanation:
To know the correct answer to the question, we shall determine the time taken for the baseball and the base runner to get to the home plate. This is illustrated below:
For the baseball:
Horizontal velocity (u) = 30 m/s
Horizontal distance (s) = 60 m
Time (t) =?
s = ut
60 = 30 × t
Divide both side by 30
t = 60 / 30
t = 2 s
Thus, it will take the baseball 2 s to get to the home plate.
For the base runner:
Horizontal velocity (u) = 5 m/s
Horizontal distance (s) = 5 m
Time (t) =?
s = ut
5 = 5 × t
Divide both side by 5
t = 5 / 5
t = 1 s
Thus, it will take the base runner 1 s to get to the home plate.
SUMMARY:
Time taken for the baseball to get to the home plate = 2 s
Time taken for the base runner to get to the home plate = 1 s
From the calculations made above, we can conclude that the base runner will arrive at the home plate first because it took him 1 s to get to the home plate whereas the baseball took 2 s to get there.
Answer:
Water flows through this type of soil.
Explanation:
By definition permeable soil is soil which water and other fluid flow easily through (like sand) If a plant needs drainage the soil will need to flow through the soil easily.
<h3>
♫ - - - - - - - - - - - - - - - ~<u>
Hello There</u>
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➷ It would be chemical energy to kinetic energy. The chemical energy from the gasoline is being transferred to kinetic energy.
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✽</u></h3>
➶ Hope This Helps You!
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➶ Have A Great Day ^-^
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Answer:
(2)
Explanation:
<u>a)Kinematics equation for the first ball:</u>
initial position is the building height
The ball reaches the ground, y=0, at t=t1:
(1)
Kinematics equation for the second ball:
initial position is the building height
the ball is dropped
The ball reaches the ground, y=0, at t=t2:
(2)
the second ball is dropped a time of 1.03s later than the first ball:
t2=t1-1.03 (3)
We solve the equations (1) (2) (3):
vo=8.9m/s
t2=t1-1.03 (3)
t2=3.29sg
(2)
b)
t1 must : t1>1.03 and t1>0
limit case: t1>1.03:
limit case: t1>0:
