Give me an atom with the following characteristics.
1 answer:
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m = mass of trampoline artist = 65 kg
v₀ = initial speed of the artist at the top of platform = 5
h = height through which the artist drop before landing on trampoline = 3 m
v = final speed of the artist just before landing on trampoline = ?
using conservation of energy
Kinetic energy of artist just before landing = initial kinetic energy at the top of platform + potential energy at the top of platform
(0.5) m v² = (0.5) m v₀² + mgh
dividing each term by "m"
(0.5) v² = (0.5) v₀² + gh
inserting the values
(0.5) v² = (0.5) (5)² + (9.8)(3)
v = 9.2
x = compression of the trampoline = ?
k = spring stiffness constant = 62000
Assuming the lowest depression point as reference line for measuring the potential energy
using conservation of energy
kinetic energy of artist + potential energy of artist before landing = spring potential energy of trampoline
(0.5) m v² + mg x = (0.5) k x²
inserting the values
(0.5) (65) (9.2)² + (65 x 9.8) x = (0.5) (62000) x²
x = 0.31 m
Answer:
Minimize the elevation or jump distance
Explanation:
The only action that minimizes, the impact force is to reduce as much as possible the height of the jump, the dog, ie the height from the jump point of the building. Since at the time of the jump its speed will increase every second at the rate of 9 [m/ s], that is this low effect of the gravitational acceleration of 9 [m/s^2]
where:
vf = final velocity [m/s]
g = gravity [m/s^2]
h = elevation [m]
As we can see while there is higher height, at a higher speed will impact the ground.