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pychu [463]
3 years ago
5

A biologist who is measuring the length of salmon as they travel upstream is collecting qualitative data. True or false ?

Chemistry
2 answers:
elena-14-01-66 [18.8K]3 years ago
4 0
The answer is false because qualitative data is describing something with words and quantitative data is describing something with numbers.
Vladimir [108]3 years ago
3 0

Answer: False

Explanation:

Qualitative data is one which can be observed with our senses such as sight, smell, touch, taste, and hearing. Qualitative observations do not involve any measurement. Example: Colour of an object

Quantitative data is one which involves measurement of data in numbers. Example: speed of an object

As the biologist is measuring the length of salmon as they travel upstream , it measures data in numbers and hence is a quantitative data and not a qualitative data.

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A salt forms in the reaction of barium with chlorine. What is the most likely formula unit of this salt?
Scrat [10]
The answer to this question would be: BaCl 2
Barium is an alkali metal with 56 atomic number. Barium located in the group 2 of the periodic table because it has 2 valence electrons. Chlorine is a nonmetal that has 1 valence electron. When react, it would need 2 chlorine for each barium as the valence electron of barium is twice the chlorine. 
6 0
3 years ago
Read 2 more answers
When the pH is high, what is tue concentration of hydrogen ions in a solution
joja [24]
Lowered cos the higher the ph the lower the hydrogen ions
5 0
3 years ago
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When a Na atom loses an electron to a Cl atom, the two atoms have opposite charges and are attracted to one another. What is the
ahrayia [7]

Answer:

Ionic bond

Explanation:

When Na loses an electron, it becomes positive ion.  

When Cl gains  an electron, it becomes negative ion.  

The electrostatic attraction between these ions is an ionic bond.

7 0
3 years ago
How many moles in 3.69 x 10^30 molecules of carbon dioxide?
Sedaia [141]

0.612 \times 10^{7} \text { moles of } \mathrm{CO}_{2} are present in 3.69 \times 10^{30} \text { molecules of } \mathrm{CO}_{2}

<u>Explanation:</u>

It is known that each mole of an element is composed of avagadro's number of molecules. So if we need to determine, we need to divide the number of molecules with the avagadro's number.

So,

    1 mol of element =6.02 \times 10^{23} molecules of element

As here 3.69 \times 10^{30} molecules of carbon di oxide is given. So the moles in it will be

   No. of moles of carbon dioxide = \frac{3.69 \times 10^{30}}{6.02 \times 10^{23}}

    No. of moles = 0.612 \times 10^{7} moles of carbon dioxide.

Thus,

0.612 \times 10^{7} of carbon dioxide are present in 3.69 \times 10^{30} \text { molecules of } \mathrm{CO}_{2}.

4 0
3 years ago
The buffer solution is used to control the pH to insure that it does not become too high because excessively basic solutions cou
oksian1 [2.3K]

Answer:

pH = 12.7

Explanation:

First, we have to calculate the [Ca²⁺] in a solution of about 250 ppm CaCO₃.

\frac{250mgCaCO_{3}}{L} .\frac{1gCaCO_{3}}{1000mgCaCO_{3}} .\frac{1molCa^{2+} }{100gCaCO_{3}} =2.5 \times 10^{-3} M

Now, let's consider the dissolution of Ca(OH)₂ in water.

Ca(OH)₂(s) ⇄ Ca²⁺(aq) + 2 OH⁻(aq)

The solubility product Ksp is:

Ksp = [Ca²⁺] × [OH⁻]²

[OH⁻] = √(Ksp/[Ca²⁺]) = √(6.5 × 10⁻⁶/2.5 × 10⁻³) = 5.1 × 10⁻² M

Finally, we can calculate pOH and pH.

pOH = -log [OH⁻] = -log (5.1 × 10⁻²) = 1.3

pH + pOH = 14 ⇒ pH = 14 - pOH = 14 - 1.3 = 12.7

5 0
3 years ago
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