The balanced equation for the reaction is as follows;
Ca(OH)₂ + 2HBr --> CaBr₂ + 2H₂O
stoichiometry of Ca(OH)₂ to HBr is 1:2
number of Ca(OH)₂ moles reacted - 0.10 mol/L x 0.1000 L = 0.010 mol
Number of HBr moles added - 0.10 mol/L x 0.4000 = 0.040 mol
1 mol of Ca(OH)₂ needs 2 mol of HBr for neutralisation
therefore 0.010 mol of Ca(OH)₂ needs - 0.010 x 2 = 0.020 mol of HBr to be neutralised
but 0.040 mol of HBr has been added therefore number of moles of HBr in excess - 0.040 - 0.020 = 0.020 mol
then pH of the medium can be calculated using the excess H⁺ ions
HBr is a strong acid therefore complete ionization
[HBr] = [H⁺]
[H⁺] = 0.020 mol / (100.0 + 400.0 mL)
= 0.020 mol / 0.5 L
= 0.040 mol/L
pH = -log[H⁺]
pH = - log [0.040 M]
pH = 1.40
pH of the medium is 1.40
The inner diameter for a steel stack that exhausts 1,200 m3/min of gases at 1 atm and 400 k is 1.45 m
<h3>What is Stack Height ?</h3>
Stack height means the distance from the ground-level elevation at the base of the stack to the crown of the stack.
If a stack arises from a building or other structure, the ground-level elevation of that building or structure will be used as the base elevation of the stack.
Given is a steel stack that exhausts 1,200 cu.m/min of gases
P= 1 atm and
T= 400 K
maximum expected wind speed at stack height of 12 m/s
The formula for the diameter of chimney

Q =1200 cu.m/min
= 1200 * 0.0166 = 19.92 cu.m/sec
Velocity = 12m/s

d= 1.45 m
Therefore The inner diameter for a steel stack that exhausts 1,200 m3/min of gases at 1 atm and 400 k is 1.45 m.
To know more about Stack Height
brainly.com/question/24625453
#SPJ4
Answer:
How may we help kind sir
Explanation:
and if this was for points thanks
a balanced chemical equation occurs when the number of the atoms involved in the reactants side is equal to the number of atoms in the products side.
Answer:

Explanation:
Hello!
In this case, according to the chemical reaction by which HBr reacts with Ba(OH)2:

We can see there is a 2:1 mole ratio between the acid and the base; thus, at the equivalent point we can write:

Therefore, for is to compute the volume of the used base, we proceed as shown below:

And we plug in to obtain:

Best regards!