Answer:
4.076g of HCl is neutralized by a dose of milke of magnesia containing 3.26g of Mg(OH)2
Explanation:
<u>Step 1:</u> The balanced equation
Mg(OH)₂(aq) + 2 HCl(aq) ⇔ 2 H₂O(l) + MgCl₂(aq)
This means that for 1 mole of Magnesium hydroxide consumed, there i s consumed 2 moles of HCl and there is produced 1 mole of MgCl2 ( and 2 moles of H2O)
<u>Step 2:</u> Calculating moles of Mg(OH)2
moles of Mg(OH)2 = mass of Mg(OH)2 / Molar mass of Mg(OH)2
moles Mg(OH)2 = 3.26g / 58.32g/mole = 0.0559 mole Mg(OH)2
<u>Step 3</u>: Calculating moles of HCl
Since there is for 1 mole Mg(OH)2 consumed, there is consumed 2 moles of HCl
There is for each 0.0559 moles of Mg(OH)2, 2*0.0559 =<u> 0.1118 moles of HCl</u> consumed.
<u>Step 4</u>: Calculating mass of HCl
mass of HCl = moles of HCl x Molar mass of HCl
mass of HCl = 0.1118 moles * 36.46 g/mole
mass of HCl = 4.076 g
4.076g of HCl is neutralized by a dose of milke of magnesia containing 3.26g of Mg(OH)2