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stepan [7]
2 years ago
8

PLS I NEED TO TURN THIS IN SOON

Physics
1 answer:
Mekhanik [1.2K]2 years ago
6 0

Answer:

Answer:

B

Explanation:

Explanation:

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The big bang produced an imprint of leftover heat called
tensa zangetsu [6.8K]
That's called the "Cosmic Microwave Background".  (CMB)
It was discovered in 1965, and its discoverers were awarded
the Nobel Prize in Physics in 1978.
7 0
3 years ago
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When a sinusoidal wave with speed 20 m/s , wavelength 35 cm and amplitude of 1.0 cm passes, what is the maximum speed of a point
vova2212 [387]

To solve this problem it is necessary to apply the concepts related to frequency as a function of speed and wavelength as well as the kinematic equations of simple harmonic motion

From the definition we know that the frequency can be expressed as

f = \frac{v}{\lambda}

Where,

v = Velocity \rightarrow 20m/s

\lambda = Wavelength \rightarrow 35*10^{-2}m

Therefore the frequency would be given as

f = \frac{20}{35*10^{-2}}

f = 57.14Hz

The frequency is directly proportional to the angular velocity therefore

\omega = 2\pi f

\omega = 2\pi *57.14

\omega = 359.03rad/s

Now the maximum speed from the simple harmonic movement is given by

V_{max} = A\omega

Where

A = Amplitude

Then replacing,

V_{max} = (1*10^{-2})(359.03)

V_{max} = 3.59m/s

Therefore the maximum speed of a point on the string is 3.59m/s

8 0
3 years ago
WILL GIVE BRAINLIEST!!!
Annette [7]

Answer:

Explanation:

Divergent Boundary

7 0
3 years ago
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What is the period of a wave traveling 5 m/s if its wavelength is 20 m/s
Ilia_Sergeevich [38]

Speed of wave is given as

v = 5 m/s

Wavelength of the wave is given as

\lambda = 20 m

now from the formula of wave time period we can say

speed = \frac{wavelength}{time period}

5 = \frac{20}{T}

T = \frac{20}{5}

T = 4 s

so it will have time period of T = 4 s

7 0
3 years ago
What is the momentum of a 248 g rubber ball traveling at 30.0 m/s?
Vikentia [17]
<span>The answer is, 7.44 kg*m/s</span>
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