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3 years ago

15

he capacitor can withstand a peak voltage of 550 VV . If the voltage source operates at the resonance frequency, what maximum vo

ltage amplitude can it have if the maximum capacitor voltage is not exceeded?

1 answer:

anygoal [31]3 years ago

4 0

Answer:

The maximum voltage is 39.08 V.

Explanation:

Given that,

Voltage = 550 V

Suppose, In an L-R-C series circuit, the resistance is 400 ohms, the inductance is 0.380 Henry, and the capacitance is $1.20\times10^{-2}\mu F$

We need to calculate the resonant frequency

Using formula of resonant frequency

$f=\dfrac{1}{2\pi\sqrt{LC}}$

Put the value into the formula

$f=\dfrac{1}{2\pi\sqrt{0.380\times1.20\times10^{-8}}}$

$f=2356.8\ Hz$

We need to calculate the maximum current

Using formula of current

$I=\dfrac{V_{c}}{X_{c}}$

$I=2\pi f C\times V_{c}$

Put the value into the formula

$I=2\pi\times2356.8\times1.20\times10^{-8}\times550$

$I=0.0977\ A$

We need to calculate the impedance of the circuit

Using formula of impedance

$Z=\sqrt{R^2+(X_{L}-X_{C})^2}$

At resonant frequency , $X_{L}=X_{C}$

So, Z = R

We need to calculate the maximum voltage

Using formula of voltage

$V=IR$

Put the value into the formula

$V=0.0977\times400$

$V=39.08\ V$

Hence, The maximum voltage is 39.08 V.

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3 years ago

Read 2 more answers

1. A base-ball of mass 0.3kg approaches the bat at a speed of 30 miles/hour and when the ball hits the bat for 0.5 s, it started

andre [41]

Answer:

I = 27kg.mi/h

Explanation:

In order to calculate the impulse of the ball, you use the following formula:

$I=m\Delta v$ $=m(v-v_o)$ (1)

m: mass of the ball = 0.3kg

v: speed of the ball after the bat hit it = 60mi/h

vo: speed of the ball before the bat hit it = 30mi/h

You replace the values of all parameters in the equation (1):

$I=(0.3kg)(60mi/h-(-30mi/h))=27kg\frac{mi}{h}$

where the minus sign of the initial velocity means that the motion of the ball is opposite to the final direction of such a motion.

The imulpse of the ball is 27 kg.miles/hour

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3 years ago

Latitude and longitude are the two coordinates that determine a specific point on the Earth’s surface. How does knowing the loca

DedPeter [7]

Answer:

hey sandra! i hope this will help you!

Explanation:

The geographic coordinate system is a reference system that uses the two angular latitude (north or south) and longitude (east or west) coordinates to determine the positions of the land surface points. These two angular coordinates measured from the center of the Earth are from a spherical coordinate system that is aligned with its axis of rotation. These coordinates are usually expressed in sexagesimal degrees:

Latitude measures the angle between any point and the equator. Latitude lines are called parallel and are circles parallel to the equator on the Earth's surface. Latitude is the distance between any point and Ecuador, measured on the meridian that passes through that point.

• All points located on the same parallel have the same latitude.

• Those who are in the north of Ecuador receive the denomination North (N).

• Those who are in the south of Ecuador receive the denomination South (S).

• It is measured from 0º to 90º.

• The latitude of 0º corresponds to Ecuador.

• The North and South poles have latitude 90º N and 90º S respectively.

The length measures the angle along the equator from any point on Earth. It is accepted that Greenwich in London is length 0 in most modern societies. The lines of length are maximum circles that pass through the poles and are called meridians.

• All points located on the same meridian have the same length.

• Those who are east of Meridian Zero receive the designation East (E).

• Those who are west of Meridian Zero receive the denomination West (O).

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By combining these two angles, the position of any point on the Earth's surface can be expressed.

6 0

3 years ago

A slab of glass has a 0.600 cm thick layer of water on top of it. A light ray strikes the water at an incident angle of 59.0°. A

Dimas [21]

Answer:

49.63 degree

Explanation:

thickness of glass slab, t = 0.6 cm

angle of incidence = 59 degree

Let r be the angle of refraction

The refractive index of glass, ng = 3/2

refractive index of water, nw = 4/3

refarctive index of glass with respect to water = ng / nw = 3 /2 ÷ 4 /3 = 9 / 8

So, by use of Snell's law

Refractive index of glass with respect to water = Sin i / Sin r

9 / 8 = Sin 59 / Sin r

9 / 8 = 0.857 / Sin r

Sin r = 0.7619

r = 49.63 degree

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3 years ago

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IrinaK [193]

Answer:

f = 1 m

Explanation:

The magnification of the lens is given by the formula:

$M = \frac{q}{p}$

where,

M = Magnification = 4

q = image distance = 5 m

p = object distance = ?

Therefore,

$4 = \frac{5\ m}{p}\\\\p = \frac{5\ m}{4}\\\\p = 1.25\ m$

Now using thin lens formula:

$\frac{1}{f}=\frac{1}{p}+\frac{1}{q}\\\\\frac{1}{f} = \frac{1}{1.25\ m}+\frac{1}{5\ m}\\\\\frac{1}{f} = 1\ m^{-1}\\\\$

<u>f = 1 m</u>

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