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-BARSIC- [3]
3 years ago
6

Latitude and longitude are the two coordinates that determine a specific point on the Earth’s surface. How does knowing the loca

tion of a point help us make maps?

Physics
1 answer:
DedPeter [7]3 years ago
6 0

Answer:

hey sandra! i hope this will help you!

Explanation:

The geographic coordinate system is a reference system that uses the two angular latitude (north or south) and longitude (east or west) coordinates to determine the positions of the land surface points. These two angular coordinates measured from the center of the Earth are from a spherical coordinate system that is aligned with its axis of rotation. These coordinates are usually expressed in sexagesimal degrees:

Latitude measures the angle between any point and the equator. Latitude lines are called parallel and are circles parallel to the equator on the Earth's surface. Latitude is the distance between any point and Ecuador, measured on the meridian that passes through that point.

• All points located on the same parallel have the same latitude.

• Those who are in the north of Ecuador receive the denomination North (N).

• Those who are in the south of Ecuador receive the denomination South (S).

• It is measured from 0º to 90º.

• The latitude of 0º corresponds to Ecuador.

• The North and South poles have latitude 90º N and 90º S respectively.

The length measures the angle along the equator from any point on Earth. It is accepted that Greenwich in London is length 0 in most modern societies. The lines of length are maximum circles that pass through the poles and are called meridians.

• All points located on the same meridian have the same length.

• Those who are east of Meridian Zero receive the designation East (E).

• Those who are west of Meridian Zero receive the denomination West (O).

• It is measured from 0º to 180º.

• The Greenwich meridian corresponds to the length 0º.

By combining these two angles, the position of any point on the Earth's surface can be expressed.

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The charge per unit length on a long, straight filament is -92.0 μC/m. Find the electric field 10.0 cm above the filament.
Pepsi [2]

Answer:

E = 1.655 x 10⁷ N/C towards the filament

Explanation:

Electric field due to a line charge is given by the expression

E = [tex]\frac{\lambda}{2\pi\times\epsilon_0\times r}[/tex]

where λ is linear charge density of line charge , r is distance of given point from line charge and ε₀ is a constant called permittivity and whose value is

8.85 x 10⁻¹².

Putting the given values in the equation given above

E = \frac{92\times10^{-6}}{2\times3.14\times8.85\times10^{-12}\times10^{-1}}

E = 1.655 x 10⁷ N/C

4 0
3 years ago
The speed of a nerve impulse in the human body is about 100 m/s. If you accidentally stub you toe in the dark, estimate the time
vodomira [7]

Answer:

0.02 s

Explanation:

Take the (+x) direction to be up.  

The average velocity v during a time interval Δt is the displacement Δx divided by Δt.  

v=Δx/Δt

 =x_f-x_i/t_f-t_i                 (1)

We assume that your height is 1.6m  

Solving [1]

Δt=Δx/v

  = 0.02 s

4 0
3 years ago
When a carpenter shuts off his circular saw, the 10.0 inch diameter blade slows from 4250 rpm to 0.00 in 4.00 s. (a) What is the
MaRussiya [10]

Answer:

(a) \alpha=-111.26rad/s

(b) s=4450.6in

(c) 8.66in

Explanation:

First change the units of the velocity, using these equivalents 1rev=2\pi rad and 1 min =60s

4250rpm(\frac{2\pi rad}{1rev})(\frac{1 min}{60 s} )=445.06rad/s

The angular acceleration \alpha the time rate of change of the angular speed \omega according to:

\alpha=\frac{\Delta \omega}{\Delta t}

\Delta  \omega=\omega_i-\omega_f

Where \omega_i is the original velocity, in the case the velocity before starting the deceleration, and \omega_f is the final velocity, equal to zero because it has stopped.

\alpha=\frac{\Delta \omega}{\Delta t} =\frac{\omega_i-\omega_f}{4}\frac{0-445.06}{4} =\frac{-445.06}{4} =-111.26rad/s

b) To find the distance traveled in radians use the formula:

\theta = \omega_i t + \frac{1}{2} \alpha t^2

\theta = 445.06 (4) + \frac{1}{2}(-111.26) (4)^2=1780.24-890.12=890.12rad

To change this result to inches, solve the angular displacement \theta for the distance traveled s (r is the radius).

\theta=\frac{s}{r} \\s=\theta r

s=890.12(5)=4450.6in

c) The displacement is the difference between the original position and the final. But in every complete rotation of the rim, the point returns to its original position. so is needed to know how many rotations did the point in the 890.16 rad of distant traveled:

\frac{890.12}{2\pi}=141.6667

The real difference is in the 0.6667 (or 2/3) of the rotation. To find the distance  between these positions imagine a triangle formed with the center of the blade (point C), the initial position (point A) and the final position (point B). The angle \gamma=\frac{2\pi}{3}=\frac{360^o}{3}=120 is between the two sides known. Using the theorem of the cosine we can find the missing side of the the triangle(which  is also the net displacement):

c^2=a^2+b^2-2abcos(\gamma)

c^2=5^2+5^2-2(5)(5)cos(\frac{2\pi}{3} )\\c^2=25+25+25\\c^2=75\\c=5\sqrt{3}=8.66in

4 0
3 years ago
At a particular instant the magnitude of the momentum of a planet is 2.05 × 10^29 kg·m/s, and the force exerted on it by the sta
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3 0
3 years ago
Two identical point charges are 3.00 cm apart. find the charge on each of them if the force or repulsion is 4.00 x 10^-7. (Use C
DanielleElmas [232]

Answer:

Charge on each is 2 x 10⁻¹⁰.

Explanation:

We know that Force between two point charges is given b the Coulomb's law as:

F = kq₁q₂/r^2

k = 9 x 10^9

r = 3.00 cm

= 0.03 m

q₁ = q₂

F = 4.00 x 10^-7

Rearranging the formula, we get:

F = k q²/r²

q² = Fr²/k

q² = 4 x 10⁻⁷ x 0.03²/(9x10⁹)

q² = 4 x 10⁻²⁰

q = 2 x 10⁻¹⁰

As there is force of repulsion between the charges, the charges must be both positive or both negative.

3 0
3 years ago
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