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3 years ago

What is the charge on an atom after it loses an electron during the formation of a bond?

2 answers:

6 0

I believe the charge is positive as losing an electron suggests that the atom lost a negative charge, leaving it with more positive than negative.

I haven't taken this in a few years very sorry if i'm wrong tho.

Pavel [41]3 years ago

3 0

Answer:

Its charge is positive

Explanation:

A neutral atom has the same amount of proton and electrons, so the charges are cancelled. When an atom loses an electron, its charge becomes positive and its exact charge is 1+. Thus, it is formatted a cation that may interact with an anion (an atom who receives an electron) to form an ionic bond.

Bare in mind that electrons have a negative charge and protons have a positive charge.

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Mass box A = 10 grams; Mass box B = 5 grams; Mass box C—made of one A and one B How many boxes of B would be required to make 30

Iteru [2.4K]

Mass box C is 10+5. (So C is 15)

But if C was 30, how many times could you put B (5) into it?

30/5 = 6

You would need 6 boxes of B to make 30 grams of C.

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3 years ago

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2 years ago

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2 years ago

How can u separate saturated, unsaturated and supersaturated solution?

Kruka [31]

Answer:

Saturated = The solution cannot dissolve any more solute at a given temperature

2) Unsaturated = solution can dissolve more solute at a given temperature.

3) Supersaturated = Solution which has more solute than its saturated solution

Explanation:

<h2>Mark me brainlist</h2>

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2 years ago

Electrochemical cells can be used to measure ionic concentrations. A cell is set up with a pair of Zn electrodes, each immersed

Phantasy [73]

Answer:

the concentration of the solution is 0.00906 M

Explanation:

Given the data in the question;

we know that from Nernst Equation;

E = E⁰ - ((0.0592/n) logQ)

now, E₀ for concentration cell is 0

n for this redox is 2

concentration of the unknown solution is x

so we substitute

0.045 = 0 - ( 0.0592 / 2)log( x/0.300 ))

0.045 = -0.0296log( x/0.300 )

divide both side by 0.0296

1.52 = -log( x/0.300 )

x/0.300 = $10^{-1.52$

x/0.300 = 0.0301995

we cross multiply

x = 0.300 × 0.0301995

x = 0.00906 M

Therefore, the concentration of the solution is 0.00906 M

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3 years ago