Explanation:
1)

Mass of NaOH = m
MOlar mass of NaOH = 40 g/mol
Volume of NaOH solution = 1.00 L
Molarity of the solution= 1.00 M


A student can prepare the solution by dissolving the 40. grams of NaOH in is small volume of water and making that whole volume of solution to volume of 1 L.
Upto two significant figures mass should be determined.
2)
(dilution equation)
Molarity of the NaOH solution = 
Volume of the solution = 
Molarity of the NaOH solution after dilution = 
Volume of NaOH solution after dilution= 


A student can prepare NaOH solution of 1.00 M by diluting the 0.500 L of 2.00 M solution of NaOH with water to 1.00 L volume.
Upto three significant figures volume should be determined.
Answer: 54.94atm
Explanation: Please see attachment for explanation
+1
Explanation:
To solve this problem, we need to set up an algebraic equation. Let us first understand the meaning of oxidation number.
The oxidation number is the formal charge assigned to an atom present in a molecule or formula unit
The algebraic sum of all oxidation numbers of atoms in an ion containing more than one kind of atom is the charge on the ion.
The algebraic sum of all oxidation number of atoms in a neutral compound is zero;
The radical NO₃ has a formal charge of -1;
let the oxidation number of Li = x
x + (-1) = 0
x = + 1
learn more:
Oxidation number brainly.com/question/10017129
#learnwithBrainly
The symbol of the period five element that is a member of the pnicitides family are antimony.
Explanation:
Pnictogen family
- In periodic table, column 15 elements are Pnitogen family.
- The pnictogen elements are Nitrogen-N, arsenic-As, phosphorus-P, bismuth-Bi, antimony-Sb, ununpentium-Uup.
- There are five valence electrons each member of pnictogen family. In group 15 double bonds and triple bonds are formed due to these valence electrons.
- Pnictides, binary compounds of group 15.
Antimony
- Antimony is the element found in period 5 and block p.
- A chemical element, Antimony (Sb) from Latin word stibium and 51 is its atomic number. It is in solid state.
- In ancient times, antimony compounds are used as cosmetic and medicine.
- Appeared as semi metal.
- Electronic configurations of Sb is [Kr] 4d105s25p3.
D. Two electrons in its first energy level; eight electrons in its second energy level; six valence electrons in its outermost energy level.
Please correct me if I'm wrong!! :)