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weeeeeb [17]
3 years ago
11

Classify each of the following processes as spontaneous or nonspontaneous

Chemistry
1 answer:
Brilliant_brown [7]3 years ago
5 0
What are the processes we are supposed to be classifying?
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The amount of water vapor in a given volume of air is ______________ .The amount of water vapor in the air at any one time depen
Eduardwww [97]

Answer:

The amount of water vapor in a given volume of air is humidity.The amount of water vapor in the air at any one time depends on temperature . Warmer air holds more water than cooler air. Clouds form when humidity is low and thetemperature is high . Relative humidity is defined as the amount of water vapor in the air divided by the amount that would have to be present in the same air to form a cloud or condense on a surface. Dew is related to the humidity of the previous day. The air temperature at which water vapor in the air condenses onto cool surfaces is the dew point.

Explanation:

8 0
2 years ago
Find the density of an object that has a mass of 6.13 g and volume of 1.50 cm³.​
storchak [24]
  • <em>Answer:</em>

<em>≈ 4.10 g/cm³</em>

  • <em>Explanation:</em>

<em>Hi there ! </em>

<em><u /></em>

<em><u>Density formula</u></em>

<em>d = m/V</em>

<em>d = 6.13g/1.5cm³</em>

<em>d = 4.08(6) g/cm³ ≈ 4.10 g/cm³</em>

<em />

<em>Good luck !</em>

8 0
3 years ago
You notice that the water in your friend's swimming pool is cloudy and that the pool walls are discolored at the water line. A q
Flauer [41]

Answer:

6,78 mL of 12,0 wt% H₂SO₄

Explanation:

The equilibrium in water is:

H₂O (l) ⇄ H⁺ (aq) + OH⁻ (aq)

The initial concentration of [H⁺] is 10⁻⁸ M and final desired concentration is [H⁺] = 10^{-7,20}, thus,

Thus, you need to add:

[H⁺] = 10^{-7,2} -10^{-8,0} = 5,31x10⁻⁸ M

The total volume of the pool is:

9,00 m × 15,0 m ×2,50 m = 337,5 m³ ≡ 337500 L

Thus, moles of H⁺ you need to add are:

5,31x10⁻⁸ M × 337500 L = 1,792x10⁻² moles of H⁺

These moles comes from

H₂SO₄ → 2H⁺ +SO₄²⁻

Thus:

1,792x10⁻² moles of H⁺ × \frac{1H_{2}SO_4 mol}{2H^{+} mol} = 8,96x10⁻³ moles of H₂SO₄

These moles comes from:

8,96x10⁻³ moles of H₂SO₄ × \frac{98,1 g}{1 mol} × \frac{100 gSolution}{12 gH_{2}SO_4 } × \frac{1 mL}{1,080 g}  =

6,78 mL of 12,0wt% H₂SO₄

I hope it helps!

8 0
3 years ago
If we find that there is a linear correlation between the concentration of carbon dioxide in our atmosphere and the global​ temp
loris [4]

Answer:

A

Explanation:

A linear correlation means the increase in one variable cause an increase in the other variable. In a graph, the linear correlation can be demonstrated by a right-slanted straight diagonal line. Therefore if an increase in carbon dioxide causes a directly proportional increase in global temperatures then the two are correlated.

3 0
3 years ago
A gas of 19 mL at a pressure of 740 mmHg can be expected to change its pressure when its volume changes to 30. mL. Express its n
Soloha48 [4]

To solve this we assume that the gas is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant temperature and number of moles of the gas the product of PV is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

 

P1V1 =P2V2

P2 = P1V1/V2

P2 = 740mmhg x 19 mL / 30 mL

<span>P2 = 468.67 mmHg = 0.62 atm</span>

6 0
3 years ago
Read 2 more answers
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