Answer:
0.992 m
Explanation:
x = (horizontal vi)t + (1/2)at²
18 = (40)t + 0
t = 0.45 s
y = (vertical vi)t + (1/2)gt²
y = 0 + (1/2)(9.8)(0.45)²
y = 0.992 m
Answer:

Explanation:
From the question we are told that
Distance b/w A&B 
Frequency 
Sound speed 
Generally the equation for wavelength is mathematically given as




Generally the destructive interference X is mathematically given by


Therefore the destructive interference is

Answer:
41.41 m
Explanation:
When force F is applied on an object of mass m for time t and velocity v₁ is created
F X t = mv₁
F = 95 N , t = .53 s, m = 655 kg
95 x .53 = 655 x v₁
v₁ = .0768 m/s
Applying conservation of momentum on man and satellite
m₁ v₁ = m₂v₂
655 x .0768 = 82 xv₂
v₂ = .6134 m/s
their relative velocity
= .6134 + .0768
= .6902 ( they are in opposite direction )
After 60 second distance between them
= 60 x .6902 m
= 41.41 m
Answer:
A major problem in all survey research is that respondents are almost always self-selected. Not everyone who receives a survey is likely to answer it, no matter how many times they are reminded or what incentives are offered.
Explanation:
<em><u>DISADVANTAGES</u></em>
Respondents may not feel encouraged to provide accurate, honest answers.
Respondents may not feel comfortable providing answers that present themselves in a unfavorable manner.
Respondents may not be fully aware of their reasons for any given answer because of lack of memory on the subject, or even boredom.
HAVE A GOOD DAY!
As it is given that the air bag deploy in time

total distance moved by the front face of the bag

Now we will use kinematics to find the acceleration




now as we know that

so we have

so the acceleration is 400g for the front surface of balloon