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garik1379 [7]
3 years ago
7

Please help on this one?

Physics
1 answer:
Lelu [443]3 years ago
6 0

The easiest way to answer this question is just to get the answer first. The answer is A with the added comment that no chemical reaction has taken place.

Layered means that the chemicals are not soluble in one another. B is not the answer.

C is eliminated by what what was said about A.

D a solution is not a pure substance (singular) by itself. There are at least 2 chemicals together.

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Describe the difference between balanced forces and action/reaction forces
Alecsey [184]
 Balanced forces<span> act on the same object and </span>Action-Reaction forces<span> act on different objects.</span>
5 0
3 years ago
Read 2 more answers
What is the difference between speed and velocity?
mixer [17]
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Hope you could get an idea from here.

Doubt clarification - use comment section.

8 0
2 years ago
Jenise is buying a car for $7,020. The TAVT rate is 9.1%.
djyliett [7]

Answer:

$7,658.82

Explanation:

<u>Sales Tax Calculations:</u>

Sales Tax Amount = Net Price x (Sales Tax Percentage / 100)

Total Price = Net Price + Sales Tax Amount

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+Sales Tax (9.1%): $ 638.82

Total Price: $ 7,658.82

Therefore, the amount of tax that Jenise has to pay on her car is $7,658.82

8 0
3 years ago
A car travels north along a straight highway at an average speed of 85 km/h. After driving 2.0 km, the car passes a gas station
jenyasd209 [6]

Constant speed is the answer

5 0
3 years ago
On a snowy day, max (mass = 15 kg) pulls his little sister maya in a sled (combined mass = 20 kg) through the slippery snow. max
sesenic [268]

Work done by a given force is given by

W = F.d

here on sled two forces will do work

1. Applied force by Max

2. Frictional force due to ground

Now by force diagram of sled we can see the angle of force and displacement

work done by Max = W_1 = Fdcos\theta

W_1 = 12*5cos15

W_1 = 57.96 J

Now similarly work done by frictional force

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Now total work done on sled

W_{net}= W_1 + W2

W_{net} = 57.96 - 20 = 37.96 J

7 0
3 years ago
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