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3 years ago

Which of these equations is balanced, and which is not balanced? Explain how you can tell.

Chemistry

1 answer:

disa [49]3 years ago

5 0

Answer:

a is balanced

Explanation:

a) reactant/ product

(2x2)=4c / 4c

(2x6)=12h / 12 h

14o / (8o+6o)=14 o

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Identify 5 basic examples of Solutions?

Elden [556K]

Coffe
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Water
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3 years ago

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Calcium nitrate tetrahydrate dissolves in cold water to the extent of 266 g per 100 cm3. What is the concentration of nitrate io

Soloha48 [4]

Answer : The correct option is, (b) 22.5 M

Explanation : Given,

Mass of calcium nitrate tetrahydrate = 266 g

Molar mass of calcium nitrate tetrahydrate = 236.15 g/mole

Volume of solution = $100cm^3=100mL$

Molarity : It is defined as the moles of solute present in one liter of solution.

Formula used :

$Molarity=\frac{\text{Mass of calcium nitrate tetrahydrate }\times 1000}{\text{Molar mass of calcium nitrate tetrahydrate }\times \text{volume of solution in ml}}$

Now put all the given values in this formula, we get:

$Molarity=\frac{266g\times 1000}{236.15g/mole\times 100ml}=11.26mole/L=11.26M$

As calcium nitrate tetrahydrate dissociate to give 1 mole of calcium ion, 2 moles of nitrate ion and 4 moles of water.

The concentration of nitrate ion = $2\times 11.26M=22.5M$

Thus, the concentration of nitrate ion is, 22.5 M

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3 years ago

An unknown gas effuses 1.66 times more rapidly than CO2. What is the molar mass of the unknown gas, given that the molar mass of

Y_Kistochka [10]

The molar mass is 16.0 grams

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The reaction below has an equilibrium constant kp=2.2×106 at 298 k. 2cof2(g)⇌co2(g)+cf4(g) calculate kp for the reaction below.

AnnZ [28]

<span>I believe the correct 2nd reaction is:</span>

cof2(g)⇌1/2 co2(g)+1/2 cf4(g)

where we can see that it is exactly one-half of the original

Therefore the new Kp is:

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4 years ago

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Calculate the change in pH when 71.0 mL of a 0.760 M solution of NaOH is added to 1.00 L of a solution that is 1.0O M in sodium

Eddi Din [679]

Explanation:

It is known that $pK_{a}$ value of acetic acid is 4.74. And, relation between pH and $pK_{a}$ is as follows.

pH = pK_{a} + log $\frac{[CH_{3}COOH]}{[CH_{3}COONa]}$

= 4.74 + log $\frac{1.00}{1.00}$

So, number of moles of NaOH = Volume × Molarity

= 71.0 ml × 0.760 M

= 0.05396 mol

Also, moles of $CH_{3}COOH$ = moles of $CH_{3}COONa$

= Molarity × Volume

= 1.00 M × 1.00 L

= 1.00 mol

Hence, addition of sodium acetate in NaOH will lead to the formation of acetic acid as follows.

$CH_{3}COONa + NaOH \rightarrow CH_{3}COOH$

Initial : 1.00 mol 1.00 mol

NaoH addition: 0.05396 mol

Equilibrium : (1 - 0.05396 mol) 0 (1.00 + 0.05396 mol)

= 0.94604 mol = 1.05396 mol

As, pH = pK_{a} + log $\frac{[CH_{3}COONa]}{[CH_{3}COOH]}$

= 4.74 + log $\frac{0.94604}{1.05396}$

= 4.69

Therefore, change in pH will be calculated as follows.

pH = 4.74 - 4.69

= 0.05

Thus, we can conclude that change in pH of the given solution is 0.05.

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3 years ago