All categories

3 years ago

Which best describes the main difference between science and pseudoscience

2 answers:

6 0

Science
DefineA body of knowledge and the process of gaining new knowledgePseudoscience
DefineSometimes a practice or a belief claims to be science, but does not follow specific criteria. Criteria that define true science include scientific experimentation, replication of results,and peer review. Beliefs and claims that do not meet these criteria are called pseudoscience

Rzqust [24]3 years ago

6 0

Answer:

Science tests and proves; pseudoscience relies on evidence that supports a belief or theory.

Explanation:

Both science and pseudoscience have been used by scientists for ages.

Science is a factual approach to a problem. It tests the reliability, repeatability, replicability and tests any hypothesis to see if there is solid evidence to support the claim. This is done by a series of experiments that test the hypothesis. Based on the results, the hypothesis can either be nullified (rejected) or accepted.

Pseudoscience on the other hand, relies on evidence but lacks scientific practices to support the claim. The method is filled with errors as there is no proof.

You might be interested in

Genetic engineering, artificial selection and cloning are examples of biotechnology

scoundrel [369]

Answer:

3.) scientific field that uses technology to purposefully change living things

Explanation:

Science can be defined as a branch of intellectual and practical study which systematically observe a body of fact in relation to the structure and behavior of non-living and living organisms (animals, plants and humans) in the natural world through experiments. One of the most important branch of science is bioengineering. Biotechnology can be defined as a high-tech process which avail scientists the opportunity or ability to modify, remove, replace and insert Deoxyribonucleic Acid (DNA) sequence in a living organism such as bacterias, animals, plants etc in order to correct a genetic disorder and to improve on their physical and chemical conditions.

For example, selective breeding also referred to as artificial selection is being used to create plants that are more resistant to certain biological diseases. Thus, this is an example of an organism being changed through technological methods commonly known as biotechnology.

Hence, the phrase which best defines biotechnology is that, it is the scientific field that uses technology to purposefully change living things.

5 0

3 years ago

I need help, please answer

Burka [1]

This being a perfect collision means no energy is lost during the collision. Because this question asks for speed and not velocity, the speed will be the same because the final energy is the same. The speed after the collision would therefore be 1.27 m/s.

7 0

4 years ago

Help with 5 and the question below. BRAINLIEST FOR THE CORRECT ANSWER! Urgent Physics help!

krok68 [10]

Sound level at distance of 15 m is given as 20 dB

so intensity at this distance is given as

$L = 10 Log\frac{I}{I_0}$

$20 = 10 Log{I}{10^{-12}}$

$I_1 = 10^{-10}W/m^2$

now if we move closer to some some distance the sound level is now 50 dB

now the intensity is given as

$L = 10 Log\frac{I}{I_0}$

$50 = 10Log\frac{I}{10^{-12}}$

$I_2 = 10^{-7}W/m^2$

now we know that

$\frac{I_1}{I_2} = \frac{r_2^2}{r_1^2}$

$\frac{10^{-10}}{10^{-7}} = \frac{r_2^2}{15^2}$

$r_2 = 47 cm$

so now the distance from friend must be 47 cm

8 0

3 years ago

A 5.00μF parallel-plate capacitor is connected to a 12.0 V battery. After the capacitor is fully charged, the battery is disconn

EastWind [94]

(a) 12.0 V

In this problem, the capacitor is connected to the 12.0 V, until it is fully charged. Considering the capacity of the capacitor, $C=5.00 \mu F$ , the charged stored on the capacitor at the end of the process is

$Q=CV=(5.00 \mu F)(12.0 V)=60 \mu C$

When the battery is disconnected, the charge on the capacitor remains unchanged. But the capacitance, C, also remains unchanged, since it only depends on the properties of the capacitor (area and distance between the plates), which do not change. Therefore, given the relationship

$V=\frac{Q}{C}$

and since neither Q nor C change, the voltage V remains the same, 12.0 V.

(b) (i) 24.0 V

In this case, the plate separation is doubled. Let's remind the formula for the capacitance of a parallel-plate capacitor:

$C=\frac{\epsilon_0 \epsilon_r A}{d}$

where:

$\epsilon_0$ is the permittivity of free space

$\epsilon_r$ is the relative permittivity of the material inside the capacitor

A is the area of the plates

d is the separation between the plates

As we said, in this case the plate separation is doubled: d'=2d. This means that the capacitance is halved: $C'=\frac{C}{2}$ . The new voltage across the plate is given by