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galina1969 [7]
3 years ago
12

If sulfur 34 undergoes alpha decay, what will I become?

Physics
1 answer:
ikadub [295]3 years ago
3 0
It will decay into Silicon-30. Because alpha particles are 2 protons and 2 neutrons with an atomic mass of 4, you minus sulfur's atomic number by 2 and get silicon. And the atomic mass is 34 - 4 which equals 30.
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Newton's second law says force (f) is equal to mass (m) times acceration (a). A scientist wants to calculate the force of an obj
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What is the best coefficient of performance for a refrigerator that cools an environment at -26.0°C and has heat transfer to ano
azamat

Answer:

COP = 4.25

Explanation:

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Cooling temperature, T_c=-26^{\circ}C=273-26=247\ K

Heating temperature, T_h=50^{\circ}C=323\ K

We need to find the coefficient of performance. It is given by :

COP=\dfrac{T_h}{T_h-T_c}

COP=\dfrac{323}{323-247}

COP = 4.25

So, the best coefficient of performance of a refrigerator is 4.45 Hence, this is the required solution.

6 0
3 years ago
The wheels of a wagon can be approximated as the combination of a thin outer hoop, of radius rh = 0.156 m and mass 5.65 kg, and
Kay [80]

Answer:

R = 0.237 m

Explanation:

To realize this problem we must calculate the moment of inertia of the wheel formed by a thin circular ring plus the two bars with an axis that passes through its center.

The moments of inertia of the bodies are additive quantities whereby we can add the mounts inertia of the ring and the two bars.

Moment of inertia ring           I1 = MR²

Moment of inertia bar            I2 = 1/12 ML²

Moment of inertia disk          I3 = ½ mR²

Let's calculate the moment of inertia of the wheel

    I = I1 + 2 I2

    I = MR² + 2 1/12 ML²

The length of the bar is ring diameter

    L = 2R

    I = 5.65 0.156² + 1/6 9.95 (2 0.156)²

    I = 0.1375 + 0.1614

    I = 0.2989 kg m²

This is the same moment of inertia of the solid disk,

Disk

     I3 = I

     I3 = ½ MR²

They give us disk density

     ρ = M / V

    M =  ρ V

    M =  ρ (pi R² e)

Done is the thickness of the disc, in general it is e= 1 cm = 0.01 m

Let's replace

       I3 = ½ ( ρ π R²) R²

       I3 = ½  ρ π e R⁴

       R⁴ = 2 I3 / ( ρ π e)

       R = ( 2  I3 / ( ρ π e)

)^{1/4}

     

      R⁴ = 2 0.2989 / (5990 π 0.01)

      R = 0.237 m

6 0
3 years ago
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