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3 years ago

If sulfur 34 undergoes alpha decay, what will I become?

1 answer:

3 0

It will decay into Silicon-30. Because alpha particles are 2 protons and 2 neutrons with an atomic mass of 4, you minus sulfur's atomic number by 2 and get silicon. And the atomic mass is 34 - 4 which equals 30.

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A positively charged particle is in the center of a parallel-plate capacitor that has charge ±Q on its plates. SUppose the dista

slamgirl [31]

Answer:

Stay the same

Explanation:

First of all, let's find how the capacitance of the capacitor changes.

Initially, it is given by

$C=\frac{\epsilon_0 A}{d}$

where

$\epsilon_0$ is the vacuum permittivity

A is the area of the plates

d is the separation between the plates

From the formula, we see that the capacitance is inversely proportional to the separation between the plates. In this problem, the distance between the plates is doubled, so the capacitance will be halved:

$C' = \frac{1}{2}C$

The potential difference across the capacitor is given by

$V= \frac{Q}{C}$

where

Q is the charge on the plates

C is the capacitance

We see that the voltage is inversely proportional to the capacitance. We said that the capacitance has halved: therefore, the potential difference across the two plates will double:

$V' = 2 V$

Now we can analyze the electric field between the plates of the capacitor, which is given by

$E=\frac{V}{d}$

we said that:

- The voltage has doubled: V' = 2 V

- The distance between the plates has doubled: d' = 2 d

therefore, the new electric field will be

$E'=\frac{2V}{2d}=\frac{V}{d}=E$

So, the electric field is unchanged. And since the force on the particle at the center is directly proportional to the electric field:

F = qE

Then the force on the particle will stay the same.

4 0

3 years ago

When a 10 V battery is connected to a resistor, 5 A of current flows through the resistor. What is the resistor's value?

SashulF [63]

Given data

*The value of battery voltage is V = 10 V

*The current flows through the resistor is I = 5 A

The formula for the resistor is given by the Ohm's law as

$R=\frac{V}{I}$

Substitute the values in the above expression as

$\begin{gathered} R=\frac{10}{5} \\ =2\text{ ohm} \end{gathered}$

7 0

1 year ago

A beam of light strikes a mirror reflects off at the angle in which it hit the mirror. which term does the diagram below illustr

zavuch27 [327]

Answer:

B.) reflection

Explanation:

3 0

3 years ago

Involuntary actions are controlled by the ____.

lisov135 [29]

D, spinal cord.
Please note that I am not 100% sure... Just taking an educated guess.

3 0

3 years ago

Read 2 more answers

In the last part of the experiment you need to investigate the behaviour of gamma radiation as it passes through air. A gamma so

andrew11 [14]

Answer:

linear cart C Vs 1/R² or log cart C Vs R

Explanation:

Gamma radiation is very high energy electromagnetic rays, but its behavior is the same as for all radiation. By the principle of conservation of energy after the radiation is emitted, it must be distributed on a spherical surface which determines the behavior of the inverse of the square.

In this experiment you are measuring the rate of counts by time (C), this must be the dependent variable since it is not controlled by the experimenter and on the other hand it measures the distance (X) this is the independent variable since it is the one that we can control.

To make a graph with this data, the counting rate must be plotted against the inverse of the squared distance (1/R²). On the Y axis the counts per second and the X 1 / R² axis, with this graph a line must be obtained.

Another graph that we can make on double logarithmic paper where the Y axis plotted the counting rate and on the X axis the distance, the slope should give -2.

C == A / R²

Log C = log A -2 log R

With either of the two graphs, the law of the inverse of the square is tested

7 0

3 years ago