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noname [10]
3 years ago
14

Antiballistic missiles (ABMs) are designed to have very large accelerations so that they may intercept fast-moving incoming miss

iles in the short time available. What is the takeoff acceleration of a 10,000-kg ABM that expels 196 kg of gas per second at an exhaust velocity of 2.50×103 m/s?
Physics
1 answer:
4vir4ik [10]3 years ago
3 0

Answer:

a = 39.2 m/s²

Explanation:

The <em>takeoff acceleration </em>of a missile or a rocket can be expressed by the equation

  • a = V₀/m * Δm/Δt - g

Where V₀ is the exhaust velocity, m is the mass of the missile, Δm is the mass of gas expelled during a timelapse Δt, and g is gravitational acceleration.

All required data is given by the problem, so now we <u>solve for a</u>:

a = 2.50x10³m/s ÷ 10,000kg * 196kg ÷ 1s - 9.8m/s²

a = 39.2 m/s²

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Answer

given,

length of rod = 21.5 cm = 0.215 m

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considering the rod is thin

I = \dfrac{1}{3}M_{rod}L^2 + [\dfrac{2}{5}M_{ball}R^2+M_{ball}(R+L)^2]

I = \dfrac{1}{3}\times 1.2 \times 0.215^2 + [\dfrac{2}{5}\times 2 \times 0.0345^2+2\times (0.0345 +0.215)^2]

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c) linear speed of the ball

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     v  =  (0.215+0.0345) x 9.25

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d) using equation of motion

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speed attained by the swing is more than free fall

  % greater = \dfrac{2.31-2.20}{2.20}\times 100

                   = 5 %

speed of swing is 5 % more than free fall

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