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noname [10]
3 years ago
14

Antiballistic missiles (ABMs) are designed to have very large accelerations so that they may intercept fast-moving incoming miss

iles in the short time available. What is the takeoff acceleration of a 10,000-kg ABM that expels 196 kg of gas per second at an exhaust velocity of 2.50×103 m/s?
Physics
1 answer:
4vir4ik [10]3 years ago
3 0

Answer:

a = 39.2 m/s²

Explanation:

The <em>takeoff acceleration </em>of a missile or a rocket can be expressed by the equation

  • a = V₀/m * Δm/Δt - g

Where V₀ is the exhaust velocity, m is the mass of the missile, Δm is the mass of gas expelled during a timelapse Δt, and g is gravitational acceleration.

All required data is given by the problem, so now we <u>solve for a</u>:

a = 2.50x10³m/s ÷ 10,000kg * 196kg ÷ 1s - 9.8m/s²

a = 39.2 m/s²

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Two boys are at the top of a waterslide at Seven Peaks Water Park. One boy (boy A) slips off the top of the tower and falls unob
Illusion [34]

Answer: boy B, same

Explanation:

Given

One boy trips off the waterslide while the other starts sliding down

As there is no horizontal velocity, both boys have to travel the same vertical distance.

Their starting vertical velocity is zero and they need to travel the same vertical distance. Therefore, both boys splash water with the same velocity.

The time taken by boy B is more than boy A as boy B will travel some horizontal distance due to slide which will increase its time to reach the bottom.

4 0
3 years ago
One way to monitor global warming is to measure the average temperature of the ocean. Researchers are doing this by measuring th
Marat540 [252]

Answer:

0.07°C

Explanation:

<u>solution:</u>

the speed of a sound in water is<u>:</u>

v(T)=1480+4(T-4°C)

<u>at 4°C the travel time is:</u>

t(4◦C) = ( 7600 × 103 m ) / (1480 m/s) = 5202.7 s

<u>5°C, the travel time is:</u>

t(5◦C) = ( 7600 × 103 m ) / (1484 m/s) = 5188.7 s

<u>one degree C corresponds to a ∆t of 14 s so temperature difference is:</u>

ΔT=1 s/14 s=0.07◦C

5 0
3 years ago
If you travel 1.7 km north from your house at noon, and at 6:00 PM you travel 5.4 km south, what is your displacement? 3.7 km no
Yakvenalex [24]

<u>Answer</u>

3.7 Km south


<u>Explanation</u>

The definition of displacement is the distance traveled in a specific direction. It is the vector quantity. We add displacements like the way we add vectors.

Taking the direction towards North to be positive (+1.7 Km), the distance towards south would be negative (-5.4 Km).

Now lets add the two values.

(+1.7) + (-5.4) = 1.7 - 5.4

                    = - 3.7 Km      But negative was towards south.

∴ Answer = 3.7 Km south.


6 0
3 years ago
A uniform meter rule with a mass of 200g is suspended at zero mark pivotes at 22.0cm mark. calculate the mass of the rule.
denpristay [2]

Answer:

The mass of the rule is 56.41 g  

Explanation:

Given;

mass of the object suspended at zero mark, m₁ = 200 g

pivot of the uniform meter rule = 22 cm

Total length of meter rule = 100 cm

0                          22cm                                  100cm

-------------------------Δ------------------------------------

↓                                                                       ↓

200g                                                                 m₂  

Apply principle of moment

(200 g)(22 cm - 0)     = m₂(100 cm - 22 cm)

(200 g)(22 cm) = m₂(78 cm)

m₂ =  (200 g)(22 cm)  / (78 cm)

m₂ = 56.41 g  

Therefore,  the mass of the rule is 56.41 g                                            

3 0
4 years ago
A force of 30 N is applied to an object with a mass of 15 kg. What is the resulting acceleration?
svet-max [94.6K]

Answer:

We know that Force = mass × acceleration

By substituting the values we get,

30 N = 15 kg × a (where a is acceleration)

Or we can write it as

15 kg × a = 30 N

Transposing 15 to RHS,

a = 30 ÷ 15 m/s²

Therefore, acceleration = 2 m/s²

pls give brainliest for the answer

5 0
3 years ago
Read 2 more answers
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