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noname [10]
3 years ago
14

Antiballistic missiles (ABMs) are designed to have very large accelerations so that they may intercept fast-moving incoming miss

iles in the short time available. What is the takeoff acceleration of a 10,000-kg ABM that expels 196 kg of gas per second at an exhaust velocity of 2.50×103 m/s?
Physics
1 answer:
4vir4ik [10]3 years ago
3 0

Answer:

a = 39.2 m/s²

Explanation:

The <em>takeoff acceleration </em>of a missile or a rocket can be expressed by the equation

  • a = V₀/m * Δm/Δt - g

Where V₀ is the exhaust velocity, m is the mass of the missile, Δm is the mass of gas expelled during a timelapse Δt, and g is gravitational acceleration.

All required data is given by the problem, so now we <u>solve for a</u>:

a = 2.50x10³m/s ÷ 10,000kg * 196kg ÷ 1s - 9.8m/s²

a = 39.2 m/s²

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Explanation:

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Thus, we can conclude that positive acceleration occurs when an object speeds up.

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mrs_skeptik [129]

Answer:

Current through each phase Vp = 2.2A

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Explanation:

i) Find current through each phase

Vp =220V (rms)

Z =100 Ω

I = Vp/Z

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ii) Find the total three phase power

for a resistive load, Power, P = VI

Power for each phase is given as:

P = 220 * 2.2

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Total power TP =3* P

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 iii) Find the power factor of the load

Phase angle for a resistive load is 0.

α= 0

Hence, power factor of load = cos α

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3 years ago
The mean diameters of Mars and Earth are 6.9 ✕ 103 km and 1.3 ✕ 104 km, respectively. The mass of Mars is 0.11 times Earth's mas
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Answer:

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We have given radius of mars R_{mars}=6.9\times 10^3km=6.9\times 10^6m and radius of earth R_{E}=1.3\times 10^4km=1.3\times 10^7m

Mass of earth M_E=5.972\times 10^{24}kg

So mass of mars M_m=5.972\times\times 0.11 \times 10^{24}=0.657\times 10^{24}kg

Volume of mars V=\frac{4}{3}\pi R^3=\frac{4}{3}\times 3.14\times (6.9\times 10^6)^3=1375.357\times 10^{18}m^3

So density of mars d_{mars}=\frac{mass}{volume}=\frac{0.657\times 10^{24}}{1375.357\times 10^{18}}=477.69kg/m^3

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