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Answer:
A force of 12.857 newtons must be applied to open the door.
Explanation:
In this case, a force is exerted on the door, a moment is performed and the door is opened. If moment remains constant, the force is inversely proportional to distance respect to axis of rotation passing through hinges. That is:
(Eq. 1)
Where:
- Force, measured in newtons.
- Proportionality ratio, measured in newton-meters.
- Distance respect to axis of rotation passing through hinges, measured in meters.
From (Eq. 1) we get the following relationship and clear the final force within:
(Eq. 2)
Where:
,
- Initial and final forces, measured in newtons.
,
- Initial and final distances, measured in meters.
If we know that ,
and
, then final force is:
A force of 12.857 newtons must be applied to open the door.
Explanation:
Given that,
Distance 1, r = 100 m
Intensity,
If distance 2, r' = 25 m
We need to find the intensity and the intensity level at 25 meters. Intensity and a distance r is given by :
.........(1)
Let I' is the intensity at r'. So,
............(2)
From equation (1) and (2) :
Intensity level is given by :
,
dB = 32.96 dB
Hence, this is the required solution.