Answer:
a) puck is subjected to both the forces of the hockey sticks in a horizontal direction,
b)the puck does not move since the sum of the forces is zero
c) changing the magnitude or direction of its applied force
Explanation:
a) The puck is subjected to both the forces of the hockey sticks in a horizontal direction, these forces are of equal magnitude and opposite direction since the puck is at rest.
In the direction of the y-axis (perpendicular to the ice) you have the weight of the disk and the normal to this weight that are also in equilibrium.
b) the puck does not move since the sum of the forces is zero, which implies that the forces of the hockey sticks are of equal magnitude and opposite direction.
c) the player has several ways to make the puck move
* slightly changing the angle of the club and therefore the direction of the force, in this case the disc comes out in the direction of this component
* inclined the stick slightly so that the force has a vertical component and the puck jumps in this direction
* Increasing the magnitude of the force so that the puck comes out in the opposite direction to the player
* The worst case, decreasing its force to zero and the disk comes out in its direction by the other force that had the same magnitude.
Answer:
7 m/s
Explanation:
Acceleration, 
Where v and u are the final and initial velocities of the Justine respectively, t is the time taken for Justin to attain final velocity.
Making v the subject then
v=at+u
Taking u as zero then
Substituting 3.5 for t, 2 as a then
v=3.5*2=7 m/s
Answer:
4.3 * 10 N
Explanation:
To calculate torque, we multiply the distance from the pivot by the perpendicular (the part of the force that acts at right angles to the displacement vector) component of the force to the displacement vector from the pivot.
torque = distance from pivot * perpendicular force
170 Nm= 0.4 m * F
F = 425 N = 4.3 * 10 N rounded off to two significant figures
