Answer:
The potential for r > rb is equal to zero.
Explanation:
For r > rb, the potential is:

Then, the net potential is:



Answer:
they move towards the positive side... that's option 2
Answer:
h = 2.087 m
Explanation:
Given
m₁ = 3 kg
v₁ = 20 m/s
m₂ = 2 kg
v₂ = - 14 m/s
In a completely inelastic collision the colliding objects stick together after the collision and move together as a single object.
In the given problem, lets assume that the balls of putty are initially moving along the y axis, upward direction being the positive y direction. And the collision occurs at the origin of the coordinate system.
We can apply the equation
vs = (m₁*v₁ + m₂*v₂) / (m₁ + m₂)
⇒ vs = (3 kg*20 m/s + 2 kg*(- 14 m/s)) / (3 kg + 2 kg)
⇒ vs = 6.4 m/s (↑)
To calculate the maximum height h attained by the combined system of two balls of putty after the the collision, we use the expression for linear motion under gravity:
vf² = vi² - 2*g*h
where
vf = 0 m/s
g = 9.81 m/s²
vi = vs = 6.4 m/s
finally we get h:
h = vi² / (2*g)
⇒ h = (6.4 m/s)² / (2*9.81 m/s²) = 2.087 m
Applying Newton's Second Law of Motion, the acceleration of the ball is 16.8 
<u>Given the following data:</u>
- Acceleration due to gravity = 9.8

To find ball's acceleration, we would apply Newton's Second Law of Motion:
First of all, we would determine the net force acting on the ball.

× 
Downward force = 4.9 N

Net force = 8.4 N
Mathematically, Newton's Second Law of Motion is given by this formula;

<em>Acceleration = 16.8 </em>
<em />
Therefore, the acceleration of the ball is 16.8 
Read more here: brainly.com/question/24029674