The tension in rope C is determined as 122.23 N.
<h3>Tension in rope C</h3>
The tension in rope C is calculated as follows;
B² = A² + C²
C² = B² - A²
C² = (752²) - (742²)
C² = 14,940
C = √14,940
C = 122.23 N
Thus, the tension in rope C is determined as 122.23 N.
Learn more about tension here: brainly.com/question/24994188
#SPJ1
Answer:
0.366×10^{-3} / s
Explanation:
θ = θmax e^{-bt/2m}
Given that
θ = 5.50°
θmax = 15.0°
So that we have
ln (θ / θmax) = -bt /2m
= - ln(5.50°/ 15.0°) / 1000s = b /2m
= b / 2m = 0.366×10^{-3} / s
Answer:
The value is 
Explanation:
From the question we are told that
The temperature is 
Generally the root mean square speed of the oxygen molecules is mathematically represented as

Here R is the gas constant with a value 
M is the molar mass of oxygen molecule with value 
So

=> 