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Setler [38]
3 years ago
13

How deep can an object with 6360N hitting on a sponge get ???

Physics
1 answer:
borishaifa [10]3 years ago
5 0

Answer:

The sponge must go \dfrac{636}{m}\ \text{meter} deep

Explanation:

If F = 6360 N, then it is required to find how deep can an object with this force hitting on a sponge get.

We know that, F = mgh

m is mass

g is acceleration due to gravity

h=\dfrac{F}{mg}\\\\h=\dfrac{6360}{10m}\\\\h=\dfrac{636}{m}\ \text{meter}

So, the sponge must go \dfrac{636}{m}\ \text{meter} deep.

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Field, In physics, a region in which each point is affected by a force.

Explanation:

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In a uranium fission reaction, uranium splits into two smaller atoms and energy. Where did the energy come from?
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Emily holds a banana of mass m over the edge of a bridge of height h. She drops the banana and it falls to the river below. Use
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Answer:

The mass of the banana is m and it is at height h.

Applying the Law of Conservation of Energy

              Total Energy before fall = Total Energy after fall

                                E_{i}  = E_{f}

Here, total energy is the sum of kinetic energy and potential energy

K.E_{i} + P.E_{i} = K.E_{f} + P.E_{f}       (a)

When banana is at height h, it has

                 K.E_{i} = 0    and    P.E_{i} = mgh          

and when it reaches the river, it has

       K.E_{f}  = 1/2mv^{2}    and   P.E_{f}  = 0

Putting the values in equation (a)

                              0 + mgh = 1/2mv^{2} + 0

                                      mgh = 1/2mv^{2}

<em>cutting 'm' from both sides</em>

<em>                                           </em>gh = 1/2v^{2}

                                          v = \sqrt{2gh}

Hence, the velocity of banana before hitting the water is

                                          v = \sqrt{2gh}

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