The answer will be C, a stopwatch :)
Answer with Explanation:
We are given that
a.General equation of electric field wave
Where 
=Amplitude of electric field wave
By comparing
a.Amplitude of electric field wave=
b.Amplitude of magnetic field wave,
Where 
Amplitude of magnetic field wave=
c.Frequency of wave,
d.Wavelength,
e.Period of wave,
f.Speed of wave,
Answer:
1. 2 N to the left
2. To the left.
Explanation:
1. Determination of the net force.
Force applied to the right (Fᵣ) = 18 N
Force applied to the left (Fₗ) = 20 N
Net force (Fₙ) =?
The net force acting on the book can be obtained as follow:
Fₙ = Fₗ – Fᵣ
Fₙ = 20 – 18
Fₙ = 2 N to the left
Thus, the net force acting on the book is 2 N to the left
2. Determination of the direction.
From 1 above, the net force acting on the book is 2 N to the left. This simply means that the book will move to the left direction.
Answer:
0.05J
Explanation:
Since the total energy is conserved I.e the mechanical energy, the energy present in the system are kinetic energy, potential energy and the gravitational potential energy. The expression for this energy is written as
Kinetic Energy=1/2MV^2
Potential Energy=1/2Kx^2
Where K is the spring constant and X is the extension the spring experience.
Gravitational Energy=mgh
Where m=mass, g=gravity constant and h=height
Hence for a spring with spring constant 10N/m and extension 0.1m the potential energy can be calculated as
PE=1/2Kx^2
If we substitute values we arrive at
PE=1/2×10×0.1^2
PE=0.05J
