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vovikov84 [41]
3 years ago
13

PLEASE ANSWER

Chemistry
1 answer:
Aleks [24]3 years ago
6 0

Answer:

The answer is B. Jeff pushes on his box with twice the amount of force since his box has 1/2 the mass of Jim's box.

hope it helps!

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If 10ml of 1.00M HCI(aq) neutralized 30 ml of an NaOH solution. What was the molarity of the Na OH solution?​
Ahat [919]

Explanation:

plz mark as brainlist///////

6 0
3 years ago
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Identify the structure of a minor product formed from the radical chlorination of propane, which has molecular formula C3H6Cl2 a
Novosadov [1.4K]

Answer:

             As we are not provided with ¹H-NMR spectrum therefore we can not conclude a single result for the minor chlorination of propane with Molecular formula C₃H₆Cl₂.

Hence, we will draw all the possible isomers with molecular formula C₃H₆Cl₂ and predict the ¹H-NMR spectrum for each of them separately.

Below is the structures of possible minor products and the NMR spectrum respectively.

Possible Product A:

                                If the minor product formed is 2,2-Dichloropropane then it will give only one singlet peak in NMR spectrum.

Possible Product B:

                               If the minor product is 1,1-Dichloropropane then it will exhibit two triplets and one multiplet as shown in figure.

Possible Product C:

                               If the minor product is 1,2-Dichloropropane then it will give four peaks in NMR. The extra peak is formed due to two enantiomers about the chiral carbon.

Possible Product D:

                               If the minor product is 1,3-Dichloropropane then it will exhibit one triplet and one quintet signal as shown in figure.

7 0
2 years ago
A 29.05 gram sample of cobalt is heated in the presence of excess oxygen. A metal oxide is formed with a mass of 40.88 g. Determ
deff fn [24]

The empirical formula of the oxide is Co₂O₃.

<em>Step 1</em>. Calculate the <em>mass of oxygen</em>

Your reaction is

 Cobalt + oxygen ⟶ cobalt oxide

29.05 g +    x g    ⟶     40.88 g

According to the <em>Law of Conservation of Mass</em>, the total mass of the reactants must equal the total mass of the products. Thus,

29.05 g + <em>x</em> g ⟶ 40.88 g

<em>x</em> = 40.88 – 29.05 = 11.83

<em>Step 2</em>. Calculate the <em>moles of each element</em>

The empirical formula is the simplest whole-number ratio of atoms in a compound.

The ratio of atoms is the same as the ratio of moles.

So, our job is to calculate the molar ratio of Co to O.

<em>Moles of Co</em> = 29.05 g Co × (1 mol Co /(58.93 g Co) = 0.492 96 mol Co

<em>Moles of </em>O = 11.83 g O × (1 mol O/16.00 g O) = 0.739 38 mol O

<em>Step 3</em>. Calculate the <em>molar ratio</em> of the elements

Divide each number by the smaller number of moles

Co:O = 0.429 26:0.739 38 = 1:1.4999

<em>Step 4</em>. Multiply each number by a factor that makes the <em>ratio close to whole numbers </em>

Multiply by 2. Then

Co:O = 2:2.998 ≈ 2:3

<em>Step 5</em>: Write the <em>empirical formula</em>

EF = Co₂O₃

4 0
3 years ago
Please help .....................
Advocard [28]

Answer:

Explanation:

The photo is not there :o

8 0
3 years ago
Suppose you want to determine which type of paper falls the fastest; an unfolded sheet of paper, a sheet of paper folded into fo
AnnZ [28]
For starters, I would get the same height for each paper, such as a counter top. Then, I would make said paper. You would use a timer of course, maybe even something like a speed gun to calculate the speed as said paper falls. You would push each paper off the counter top and calculate the speed for each paper. This is the easiest way to prove your hypothesis.
3 0
3 years ago
Read 2 more answers
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