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miskamm [114]
3 years ago
7

Nurse Antonio measured out 7 grams of sodium chloride (NaCI). Using dimensional analysis, calculate how many moles of NaCI he we

ighed out.
Chemistry
1 answer:
Neporo4naja [7]3 years ago
6 0

Answer:

0.119 moles

Explanation:

Given that,

Mass measured by Nurse Antonio is 7 grams of NaCl

To find,

The no of moles of NaCl

Solution,

The number of moles is given by

n=\dfrac{m}{M}

m is given mass

M is molar mass

For NaCl, molar mass is 23+35.5 = 58.5 grams

So,

n=\dfrac{7}{58.5}\\\\n=0.119\ \text{moles}

Therefore, there are 0.119 moles of NaCl.

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Choose the predominant type of bonding as ionic, covalent, or metallic for the substance below. NiSn
podryga [215]

Answer:

Metallic.

Explanation:

Hello,

In this case, when nickel and tin bond, the difference in their electronegativities results:

\Delta E=E_{Sn}-E_{Ni}=1.96-1.91=0.05

Such difference, in addition to the fact that nickel is a transition metal and tin a metal, will suggest that the predominant type of bond for this substance is metallic as the attractive force between the conduction of electrons and positively charged metal ions is present.

Best regards.

8 0
3 years ago
Number of representative particles in 3 moles Sn
AURORKA [14]

Answer:

18.066 × 10²³ particles

Explanation:

Given data:

Number of moles of Sn = 3 mol

Number of representative particles = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

For 3 mole of Sn:

3 × 6.022 × 10²³ particles

18.066 × 10²³ particles

5 0
3 years ago
Suppose you are a particle og watet in a lake. Describe what happens to you when a motorboat passes by.
Tamiku [17]

i will move and collapse with other h20 particles and splash around


3 0
4 years ago
Can someone please help me on #17? I don’t get it :(
Dmitry [639]
Given is the specific heat of water equal to 4.18 Joule per gram per *C.

This means to raise the temperature of 1 g of water by 1 degree Celsius we need 4.18 joule of energy.

Now, look at the question. We are asked that how much amount of energy would be required to raise the temperature of 25 g of water by (54-50) = 4 degree celsius.

To do so we have formula

Q = m C (temperature difference)

Have a look at pic for answer

5 0
3 years ago
I need help with 4, 5, 8, 9, and 6. Quickly I need it before class starts. Worth points!!!!!! HelP
GalinKa [24]

Answer:

4. 264.6J

5. 37.5J

6. 96J

7. 55Watts

8. 77.14m

9. 6s

10. 750Watts

Explanation:

4). Mechanical energy (potential energy) = mass (m) × acceleration due to gravity (g) × height (h)

m = 3kg, h = 9m, g = 9.8m/s²

P.E = 3 × 9 × 9.8

= 264.6J

5). Kinetic energy (K.E) = 1/2 × m × v²

Where;

m = mass (kg) = 3kg

v = velocity (m/s) = 5m/s

K.E = 1/2 × 3 × 5²

K.E = 1/2 × 3 × 25

K.E = 1/2 × 75

K.E = 37.5J

6). Work done (J) = Force (N) × distance (m)

Force = 12N, distance = 8m

Work done = 12 × 8

= 96J

7). Power = work done (J) ÷ time (s)

Work done = 550J, time = 10s

Power = 550/10

= 55Watts.

8). Work done = force (F) × distance (m)

Work done = 540J, force = 7N, distance = ?

540 = 7 × d

540 = 7d

d = 540/7

d = 77.14m

9). Power = work done (J) ÷ time (s)

Work done = 300J, time = ?, Power = 50Watts.

50 = 300/t

50t = 300

t = 300/50

t = 6seconds.

10). Power = work done (J) ÷ time (s)

This means that;

Power = force × distance / time

Force = 300N, distance = 5m, time = 2s

Power = 300 × 5 ÷ 2

Power = 1500 ÷ 2

Power = 750Watts

3 0
3 years ago
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