8 moles of water on the right side.
An oxidation-reduction or redox reaction is a reaction that involves the transfer of electrons between chemical items (the atoms, ions, or molecules involved in the reaction).
Redox reactions: the burning of fuels, the corrosion of metals, and even the processes of photosynthesis and cellular respiration involve oxidation and reduction.
Step 1:
MnO4- ----> Mn2+
2Cl- ------> Cl2
Step 2:
MnO4- --> Mn2+ + 4H2O
2Cl- -----> Cl2
Step 3:
8H+ + MnO4- ------> Mn2+ + 4H2O
2Cl- ----->Cl2
Step 4:
8H+ + MnO4- +5e- ------>Mn2+ + 4H2O
2Cl- ----> Cl2+ 2e-
Step 5:
16 H+ +2 MnO4- +10Cl- ----->2 Mn2+ + 8H2O+5Cl2
This is the balanced equation in an acidic medium.
That is 8, right side.
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The particles<span> that completely went through passed through the empty space in the atom. The </span>particles<span>that were </span>deflected<span> to the sides were deflated by a passing electron that moved the alpha </span>particle<span> out of the way. The </span>particles<span> that were bounced back hit the nucleus in the center that it bounced off.
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hoped that helped
Answer:
8.2763 g
Explanation:
Considering the Henderson- Hasselbalch equation for the calculation of the pH of the buffer solution as:
pH=pKa+log[base]/[acid]
Where Ka is the dissociation constant of the acid.
Given that the acid dissociation constant = 3.5×10⁻⁸
pKa = - log (Ka) = - log (3.5×10⁻⁸) = 7.46
Given concentration of acid = [acid] = 0.244 M
pH = 6.733
So,
6.733 = 7.46+log[base]/0.244
[Base] = 0.0457 M
Given that Volume = 2 L
So, Moles = Molarity × Volume
Moles = 0.0457 × 2 = 0.0914 moles
Molar mass of potassium hypochlorite = 90.55 g/mol
Mass = Moles × Molar mass = (0.0914 × 90.55) g = <u>8.2763 g</u>
Answer:
I think stirring is the right answer
