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Effectus [21]
3 years ago
8

A hardware salesman measures the mass of a box containing

Chemistry
2 answers:
sattari [20]3 years ago
8 0

Step 1

<u>find the mass of a single washer</u>

Divide the total mass by the number of washers

\frac{0.4168}{1000} =0.0004168\ Kg

0.0004168kg=4.168*10^{-4} kg

Step 2

<u>Convert kg to mg</u>

we know that

1 kg=1*10^{6} mg

so

4.168*10^{-4}*10^{6} =4.168*10^{2}mg=416.8 mg

therefore

<u>the answer is</u>

416.8 mg

marysya [2.9K]3 years ago
7 0
In this question, the box with 1000 washers has 0.4168kg mass. Then, to find the mass of a single washer you need to divide the mass with the number of washers. Then, you need to convert the unit into milligrams(1kg= 10^6mg)
It would be 0.4168 kg / 1000 * 10^6 milligram/kg= 4168mg.
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Misha Larkins [42]

Answer:

The correct answer is 199.66 grams per mole.

Explanation:

Based on law of effusion given by Graham, a gas rate of effusion is contrariwise proportionate to the square root of molecular mass, that is, rate of effusion of gas is inversely proportional to the square root of mass. Therefore,  

R1/R2 = √ M2/√ M1

Here rate is the rate of effusion of the gas expressed in terms of number of mole per uni time or volume, and M is the molecular mass of the gas.  

Rate Q/Rate N2 = √M of N2/ √M of Q

The molecular mass of N2 or nitrogen gas is 28 grams per mole and M of Q is molecular mass of Q and based on the question Q needs 2.67 times more to effuse in comparison to nitrogen gas, therefore, rate of Q = rate of N2/2.67

Now putting the values we get,  

rate of N2/2.67/rate of N2 = √28/ √M of Q

√M of Q = √ 28 × 2.67

M of Q = (√ 28 × 2.67)²

M of Q = 199.66 grams per mole

3 0
3 years ago
the gas left in an used aerosol can is at a pressure of 103 kPa at 25 degrees celsius if this can be thrown into fire what is th
Rainbow [258]
Hello!

The pressure of the gas when it's temperature reaches 928 °C is 3823,36 kPa

To solve that we need to apply Gay-Lussac's Law. It states that the pressure of a gas when the volume is left constant (like in the case of a sealed container like an aerosol can) is proportional to temperature. This is the relationship derived from this law that we use to solve this problem:

P2= \frac{P1}{T1}*T2= \frac{103 kPa}{25}*928=3823,36 kPa

Have a nice day!
5 0
3 years ago
Read 2 more answers
Give the orbital notation for a neutral atom of titanium
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Answer:

Explanation:

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2 years ago
How many moles are in 1.20 x 10^21 atoms of Phosphorus?
Ludmilka [50]

Answer:

You would get 19.969 moles

Explanation:

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2 years ago
2MG+O2 ...........2MGO
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Mg + 1/2 O2 → MgO

1 mol = 24 g of Mg

X mol = 12 g of Mg

x = 0.5 moles of Mg

Mg :MgO = 1:1 (coefficient from equations using mole ratio)

So

0.5 moles of MgO

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0.5 moles of MgO = 0.5 × 40

= 20 g of MgO produced
5 0
2 years ago
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