All categories

3 years ago

What is the potential difference across a light bulb when there is 32 A of current and 8 Ω of resistance from the filament.

Chemistry

1 answer:

evablogger [386]3 years ago

7 0

Answer:

force ε: the increase in potential energy per unit charge provided by the chemical reactions in the battery. And the voltage difference across the light bulb is: ∆V = I R = (0.06 A)(20 Ω) = 1.2 V ▪If we measure the voltage difference across the battery or the light bulb, we will get 1.2 V.

Explanation:

please mark this answer as brainlest

You might be interested in

A chemist conducted a study on ammonia NH3(g) into hydrogen gas and nitrogen gas. This reaction is represented by the following

Lelu [443]

Answer:

Explanation:

7 0

3 years ago

A 10 gram sample of iron reacts with oxygen to form 18.2 grams of ferric oxide. How many grams of oxygen reacted?

RoseWind [281]

Answer:

$\boxed {\boxed {\sf 8.2 \ grams}}$

Explanation:

According to the Law of Conservation of Mass, the mass of the products must equal the mass of the reactants.

mass products = mass reactants

In this problem, the reaction is:

$iron + oxygen = ferric \ oxygen$

The reactants are iron and oxygen. We know the mass of the iron sample is 10 grams.

The product is ferric oxide. The mass of the ferric oxide sample is 18.2 grams.

$10 \ g + oxygen=18.2 \ g$

We want to find how many grams of oxygen reacted. We have to get the oxygen by itself. 10 is being added to oxygen. The inverse of addition is subtraction. Subtract 10 from both sides of the equation.

$10 \ g - 10 \ g+ oxygen = 18.2 \ g - 10 \ g$

$oxygen= 18.2 \ g - 10 \ g$

$oxygen= 8.2 \ g \\$

8.2 grams of oxygen reacted with 10 grams of iron to form 18.2 grams of ferric oxide.

8 0

3 years ago

Balancing equations I'll give brainliest.

wel

Answer:

You should follow these steps:

Count each type of atom in reactants and products.

Place coefficients, as needed, in front of the symbols or formulas to increase the number of atoms or molecules of the substances.

Repeat steps 1 and 2 until the equation is balanced.

Explanation:

7 0

3 years ago

Chemistry, please help! Thanks.

Ilya [14]

Answer:

d. The gold(III) ion is most easily reduced.

Explanation:

The standard reduction potentials are

Au³⁺ + 3e⁻ ⟶ Au; 1.50 V

Hg²⁺ + 2e⁻ ⟶ Hg; 0.85 V

Zn²⁺ + 2e⁻ ⟶ Zn; -0.76 V

Na⁺ + e⁻ ⟶ Na; -2.71 V

A more positive voltage means that there is a stronger driving force for the reaction.

Thus, Au³⁺ is the best acceptor of electrons.

Reduction Is Gain of electrons and, Au³⁺ is gaining electrons, so

Au³⁺ is most easily reduced.

4 0

3 years ago

T or F: The mass of an answer is so small it is rounded to 0 amu

Nutka1998 [239]

True because it doesn’t count as a full number

6 0

3 years ago