Answer:
C. One mole of water was produced from this reaction.
Explanation:
- From the balanced equation:
<em>2H₂ + O₂ → 2H₂O,</em>
It is clear that 2 mol of H₂ react with 1 mol of O₂ to produce 2 mol of H₂O.
- So, if one mole of hydrogen was used in this reaction:
1/2 mol of O₂ was used in the reaction, and
1 mol of water was produced from this reaction.
- So, the correct statement is:
<em>C. One mole of water was produced from this reaction.
</em>
Molarity of a solution if 124.86 g of rbf are dissolved into a solution of water that has a final volume of 2.00L is 0.59.
<h3>What is molarity?</h3>
Molarity is used for dilute aqueous solutions held at a constant temperature. In general, the difference between molarity and molality for aqueous solutions near room temperature is very small and it won't really matter whether you use a molar or molal concentration.
MOLARITY = no of moles of solute/volume of soln in litres
No of moles of rbf = 124.6/104.46
= 1.19
Volume of soln = 2
Molarity=1.19/2 = 0.59
Learn more about Molarity here: brainly.com/question/26756988
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He would study it so he could see how it interacted with the living things around it.
<span>Mixing an acid and a base results in neutralization, but the results are potentially dangerous. No matter which acid or base is used, the resulting solution is water and varying types of salt. The process of neutralization often involves the substances heating up when they come together. If the solution heats up too much or too fast, a violent explosion or the creation of harmful or flammable gases is a possibility. This occurs when the chemicals are mixed too quickly, the acid and base are too strong or if there is no available salt to be made in the solution.</span>
Answer #1 is "there is 2.5 grams of solute in every 100 g of solution."
We calculate for 2.5% by mass solution by dividing the mass of the solute by the mass of the solution and then multiply by 100.
Answer #2 is "that mass ratio would be 2.5/100 or 2.5 grams of solute/100 grams of solution."
We weigh out 2.5 grams of solute and then add 97.5 grams of solvent to make a total of 100 gram solution, that is,
mass of solute / mass of solution = 2.5g solute / (2.5g solute + 97.5g solvent)
= 2.5g solute / 100g solution
Answer#3 is "a solution mass of 1 kg is 10 times greater than 100 g, thus one kilogram (1 kg) of a 2.5% ki solution would contain 25 grams of ki."
We multiply 10 to each mass so that 100 grams becomes 1000grams since 1000 grams is equal to 1 kg:
mass of solute / mass of solution = 2.5g*10/[(2.5g*10) + (97.5g*10)]
= 25g solute/(25g solute + 975g solvent)
= 25g solute/1000g solution
= 25g solute/1kg solution
