I think this one is the organelles.
In 1869 he published a table of the elements organized by increasing atomic mass.
Mendeleev is called the "father of the modern periodic table
stated that if the atomic weight of an element caused it to be placed in the wrong group, then the weight must be wrong. (He corrected the atomic masses of Be, In, and U)
was so confident in his table that he used it to predict the physical properties of three elements that were yet unknown.
After the discovery of these unknown elements between 1874 and 1885, and the fact that Mendeleev's predictions for Sc, Ga, and Ge were amazingly close to the actual values, his table was generally accepted.
However, in spite of Mendeleev's great achievement, problems arose when new elements were discovered and more accurate atomic weights determined.
STOP DELETING MY COMMENTS PEOPLE PLEASE!!!!!!!!!
Answer:
357 g of the transition metal are present in 630 grams of the compound of the transition metal and iodine
Explanation:
In any sample of the compound, the percentage by mass of the transition metal is 56.7%. This means that for a 100 g sample of the compound, 56.7 g is the metal while the remaining mass, 43.3 g is iodine.
Given mass of sample compound = 630 g
Calculating the mass of iodine present involves multiplying the percentage by mass composition of the metal by the mass of the given sample;
56.7 % = 56.7/100 = 0.567
Mass of transition metal = 0.567 * 630 = 357.21 g
Therefore, the mass of the transition metal present in 630 g of the compound is approximately 357 g
This is known as polymerisation
Answer:
CO + 2H2 = CH3OH
Explanation:
1. Label Each Compound With a Variable
aCO + bH2 = cCH3OH
2. Create a System of Equations, One Per Element
C: 1a + 0b = 1c
O: 1a + 0b = 1c
H: 0a + 2b = 4c
3. Solve For All Variables (using substitution, gauss elimination, or a calculator)
a = 1
b = 2
c = 1
4. Substitute Coefficients and Verify Result
CO + 2H2 = CH3OH
L R
C: 1 1 ✔️
O: 1 1 ✔️
H: 4 4 ✔️
