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3 years ago

Chief cells ________. produce hcl produce mucin produce gastrin produce pepsinogen

1 answer:

5 0

We are being asked of the location and function of the Chief Cells. Well, Cheif Cells is located and found in the basal regions of the gastric glands.Another thing is it can produce HCl which is a chemical term for Hydrochloric Acid. This HCl component is secreted by this gland which is located in humans stomach.

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What are 4 examples of sediment that may become sedimentary rock

jeka94

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3 years ago

Determine the value of the equilibrium constant, KgoalKgoalK_goal, for the reaction CO2(g)⇌C(s)+O2(g)CO2(g)⇌C(s)+O2(g), Kgoal=?

NISA [10]

Answer:

The value of the equilibrium constant for reaction asked is $1.24\times 10^{-7}$ .

Explanation:

$CO_2(g)\rightleftharpoons C(s)+O_2(g)$

$K_{goal}=?$

$K_{goal}=\frac{[C][O_2]}{[CO_2]}$

$2CO_2(g)+2H_2O(l)\rightleftharpoons CH_3COOH(l)+2O_2(g)$ ..[1]

$K_1=\frac{[CH_3COOH][O_2]^2}{[CO_2]^2[H_2O]^2}$

$2H_2(g)+O2(g)\rightleftharpoons 2H_2O(l)$ ..[2]

$K_2=\frac{[H_2O]^2}{[H_2]^2[O_2]}$

$CH_3COOH(l)\rightleftharpoons 2C(s)+2H_2(g)+O_2(g)$ ..[3]

$K_3=\frac{[C]^2[H_2]^2[O_2]}{[CH_3COOH]}$

[1] + [2] + [3]

$2CO_2(g)\rightleftharpoons 2C(s)+2O_2(g)$

( on adding the equilibrium constant will get multiplied with each other)

$K=K_1\times K_2\times K_3$

$K=5.40\times 10^{-16}\times 1.06\times 10^{10}\times 2.68\times 10^{-9}$

$K=1.53\times 10^{-14}$

$K=\frac{[C]^2[O_2]^2}{[CO_2]^2}$

On comparing the K and $K_{goal}$ :

$K^2=K_{goal}$

$K_{goal}=\sqrt{K}=\sqrt{1.53\times 10^{-14}}=1.24\times 10^{-7}$

The value of the equilibrium constant for reaction asked is $1.24\times 10^{-7}$ .

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3 years ago

Which of the following gives the correct possible values of l for n = 4?

Delicious77 [7]

The answer to your question is a 12

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4 years ago

Read 2 more answers

A class investigated the reactivity of four metals by dropping little pieces of the

Pavlova-9 [17]

The least reactive metal is lead, since it reacted with none of the salt solutions.

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3 years ago

A compound with a molar mass of 100.0 g/lol has an elemental composition of 24.0% C, 3.0% H, 16.0% O and 57.0%F. What is the mol

ch4aika [34]

If I made no mistake in calculation, the given answer must be correct...(tried my best)

elements   :                       carbon     hydrogen    oxygen       Fluorine

composition [C]                     24           3                16                57

M r                                          12             1                16                19

(divide C by Mr)                       2               3                 1                  3

(Divide by smallest value)       2                3                  1                  3

(smallest value = 1...so all value remained constant)

Empirical formula : C2H3OF3

if molar mas = 100 g per mole, then

first step calculate Mr. of empirical formula: [= 100]

Them molecular formula = empirical formula

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3 years ago