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2 years ago

8

How close would you have to bring 1 C of positive chargeand 1 C of negative charge for them to exert forces of 1 N onone another

?

1 answer:

Harman [31]2 years ago

4 0

Answer:

94,800 m

Explanation:

F = kq1 q2/r^2

1 = 9 x 10^9 x 1 / r^2

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If you push on the wall with a force of 400 N, what is the magnitude of the force at the wall exerts on you?

Inessa05 [86]

Answer:

400 N

Explanation:

Due to action-Reaction, the wall pushes back on the person with a force of equal magnitude and in opposite direction to the force exerted by the person.

So the magnitude must be also 400 N.

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3 years ago

What is net netforce?

melisa1 [442]

In mechanics, the net force is the vector sum of forces acting on a particular or object

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3 years ago

What type(s) of energy is/are contained in a roller coaster car after it has come to a complete stop at the station? A. kinetic

blondinia [14]

Answer:

I think it is just potential

Explanation:

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3 years ago

Venus has an average distance to the sun of 0.723 AU. In two or more complete sentences, explain how to calculate the orbital pe

Mice21 [21]

As per the question the distance of venus from sun is given as 0.723 AU

We have been asked to calculate the time period of the planet venus.

As per kepler's laws of planetary motion the square of time period of planet is directly proportional to the cube of semi major axis. mathematically

$T^{2} \alpha R^{3}$

⇒ $T^{2} = KR^{3}$ where is k is the proportionality constant

We may solve this problem by comparing with the time period of the earth . We know that time period of earth is 365.5 days

Hence $T_{1} =365.5 days$

The distance of sun from earth is taken as 1 AU i.e the mean distance of earth from sun

Hence $R_{1} =1 AU$

The distance of venus from sun is 0.723 AU i.e $R_{2} =0.723$

From keplers law we know that- $\frac{T_{1} ^{2} }{T_{2} ^{2} } =\frac{R_{1} ^{3} }{R_{2} ^{3} }$

⇒ $T_{2} ^{2} =T_{1} ^{2} *\frac{R_{2} ^{3} }{R_{1} ^{3} }$

Putting the values mentioned above we get-

$T_{2} ^{2} =50,350.132851075$

⇒ $T_{2} =\sqrt{50,350.132851075}$

⇒ $T_{2} = 224.388352752710 days.$

Hence the time period of venus is 224.388352752710 days

7 0

4 years ago

Read 2 more answers

. The artificial sweetener NutraSweet is a chemical called aspartame (C14H18N2O5). What is (a) its molecular mass (in atomic mas

loris [4]

The molecular mass, in atomic mass unit, of aspartame would be 294 amu while the mass, in kg, of an aspartame molecule would be 0.294 kg

Aspartame has the chemical formula C14H18N2O5

C = 12, H = 1, N = 14, O = 16

(a) Molecular weight = (12x14) + (1x18) + (14x2) + (16x5)

= 168 + 18 + 28 + 80

= 294 amu

(b) Mass of 1 molecule of aspartame = mole x molar mass

= 1 x 294

= 294 g

Converting 294 g to kg = 294/1000

= 0.294 kg

More on mole and molar mass can be found here: brainly.com/question/6613610

7 0

2 years ago