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yawa3891 [41]
3 years ago
6

given a circuit powered at 12V with R1, R2, R3 respectively of 10,20,30 Ohm, determine R4 in such a way that the Wheatstone brid

ge is in equilibrium and then calculate voltages and currents as for reference exercise.​
Physics
1 answer:
elena55 [62]3 years ago
5 0

Answer:

The balanced condition for Wheatstones bridge is  

Q

P

​  

=  

S

R

​  

 

as is obvious from the given values.

No, current flows through galvanometer is zero.

Now, P and R are in series, so

Resistance,R  

1

​  

=P+R

=10+15=25Ω

Similarly, Q and S are in series, so

Resistance R  

2

​  

=R+S

=20+30=50Ω

Net resistance of the network as R  

1

​  

 and R  

2

​  

 are in parallel

i=  

R

V

​  

=  

50

6×3

​  

=0.36 A.

Explanation:

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Answer:

0.6 Ω

Explanation:

As shown in the diagram below,

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Applying ohm's law,

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make R the subject of the equation

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Substitute into equation 2

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