If I could snap my fingers and move Earth to an orbital distance at 9 AU, what would happen to the strength of the Sun's gravita
1 answer:
Answer:
= 1.2 10⁻²
force of attraction of the sun decreases by a factor of 1.2 10⁻² times
Explanation:
The force of gravity is given by the universal law of attraction
F = G m Ms / r²
where m is the mass of the Earth, Ms the mass of the Sun and r the distance from the Earth to the Sun
for the initial orbit
F₀ = G m Ms / R₀²
for one orbit
R = 9R₀
F =
F =
we substitute
F = F₀ / 81
= 1.2 10⁻²
therefore the force of attraction of the sun decreases by a factor of 1.2 10⁻² times
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Answer:
Explanation:
The horizontal distance covered by the ball in the falling is only determined by its horizontal motion - in fact, it is given by
where
is the horizontal velocity
t is the time of flight
The time of flight, instead, is only determined by the vertical motion of the ball: however, in this problem the vertical velocity is not changed (it is zero in both cases), so the time of flight remains the same.
In the first situation, the horizontal distance covered is
in the second case, the horizontal velocity is increased to
And so the new distance travelled will be
So, the distance increases linearly with the horizontal velocity.