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2 years ago

In what atmospheric layer do we find the highest concentration of ozone? the highest average air temperature?

1 answer:

7 0

The Stratosphere contains the highest concentration of the ozone, this is because the ozone is located here. The Thermosphere has the highest average air temperature also seen as the hot layer, and the Mesosphere is the lowest average sir temperature.

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A cylindrical water tank has a diameter of 9 ft and a height of 12 ft. the water surface is 2 ft from the top. about how much wa

slavikrds [6]

I think the answer your looking for is 636 ft ^3

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3 years ago

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Which statements accurately describe electronic tools? Check all that apply.

levacccp [35]

Answer:

Electronic tools provide accurate data

Explanation:

The sentence "Electronic tools provide accurate data analysis" is the only correct of all the options shown, because it is the only sentence that describes a characteristic present in all the electronic tools. The other options are not all electronic tools, but each option represents a type of electronic tool, depending on the time and technology used to build the tool.

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2 years ago

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One string of a certain musical instrument is 70.0 cm long and has a mass of 8.79 g . It is being played in a room where the spe

Svetach [21]

To solve this problem we will apply the concepts of linear mass density, and the expression of the wavelength with which we can find the frequency of the string. With these values it will be possible to find the voltage value. Later we will apply concepts related to harmonic waves in order to find the fundamental frequency.

The linear mass density is given as,

$\mu = \frac{m}{l}$

$\mu = \frac{8.79*10^{-3}}{70*10^{-2}}$

$\mu = 0.01255kg/m$

The expression for the wavelength of the standing wave for the second overtone is

$\lambda = \frac{2}{3} l$

Replacing we have

$\lambda = \frac{2}{3} (70*10^{-2})$

$\lambda = 0.466m$

The frequency of the sound wave is

$f_s = \frac{v}{\lambda_s}$

$f_s = \frac{344}{0.768}$

$f_s = 448Hz$

Now the velocity of the wave would be

$v = f_s \lambda$

$v = (448)(0.466)$

$v = 208.768m/s$

The expression that relates the velocity of the wave, tension on the string and linear mass density is

$v = \sqrt{\frac{T}{\mu}}$

$v^2 = \frac{T}{\mu}$

$T= \mu v^2$

$T = (0.01255kg/m)(208.768m/s)^2$

$T = 547N$

The tension in the string is 547N

PART B) The relation between the fundamental frequency and the $n^{th}$ harmonic frequency is

$f_n = nf_1$

Overtone is the resonant frequency above the fundamental frequency. The second overtone is the second resonant frequency after the fundamental frequency. Therefore

$n=3$