<span>Step 1 is to determine the mass of each part
Mass of Ca is 40.08 g
Mass of C is 12.01 g
Mass of O is 16.00 x 3 = 48.00 g
Step 2 is to determine the total mass of the compound
Total mass of CaCO3 is 40.08 + 12.01 + 48.00 = 100.09 g
Step 3 is to determine the % of each part using the following formula:
Mass of part / total mass x 100 =
40.08 / 100.09 x 100 = 40.04 % Ca
12.01 / 100.09 x 100 = 12.00 % C
48.00 / 100.09 x 100 = 47.96 % O
Step 4 is to double check by adding all percentages. If they equal 100, then I probably did it right. :)
40.04
+12.00
+47.96
=100.00</span><span>
</span>
The molar mass of calcium carbonate is 100 mg/mmol, so the
number of moles is:
moles CaCO3 = 500 mg / (100 mg/mmol) = 5 mmol
We see that there is 1 mole of Ca per 1 mole of CaCO3,
therefore:
<span>mass Ca = 5 mmol * (40.08 mg/mmol) = 200.22 mg</span>