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stepan [7]
4 years ago
11

How can you determine whether its bonds are ionic or covalent?

Chemistry
1 answer:
cestrela7 [59]4 years ago
5 0
There is a couple different ways to determine if<span> a </span>bond<span> is </span>ionic or covalent<span>. By definition, an </span>ionic bond<span> is between a metal and a nonmetal, and a </span>covalent bond<span> is between 2 nonmetals. So you usually just look at the periodic table and </span>determine whether<span> your compound is made of a metal/nonmetal or is just 2 nonmetals</span>
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In a particular mass of kau(cn)2, there are 6.66 × 1020 atoms of gold. What is the total number of atoms in this sample?
Vinvika [58]

Total number of atoms in the sample is the sum of number of atoms of all the elements present in the sample.

Number of gold, Au atoms in KAu(CN)_2 = 6.66\times 10^{20} atoms     (given)

From the formula of compound that is KAu(CN)_2 it is clear that the number of potassium and gold are same whereas those of carbon and nitrogen are 2 times of them.

So, the number of atoms of each element is:

Number of potassium, K atoms in KAu(CN)_2 = 6.66\times 10^{20} atoms    

Number of carbon, C atoms in KAu(CN)_2 = 2\times6.66\times 10^{20} atoms = 13.32\times 10^{20}

Number of nitrogen, N atoms in KAu(CN)_2 = 2\times6.66\times 10^{20} atoms = 13.32\times 10^{20}

Total number of atoms in KAu(CN)_2 = Number of gold, Au atoms+Number of potassium, K atoms +Number of carbon, C atoms + Number of nitrogen, N atoms

Total number of atoms in KAu(CN)_2 = 6.66\times 10^{20}+6.66\times 10^{20}+13.32\times 10^{20}+13.32\times 10^{20}

Total number of atoms in KAu(CN)_2 = 39.96\times 10^{20} atoms

Hence, the total number of atoms in KAu(CN)_2 is 3.996\times 10^{21} atoms.

7 0
3 years ago
If u pass a curve of 3A in a time of 90mins. how much mg will be deposited.​
Maslowich

Answer:

\boxed{\text{2.0 g}}

Explanation:

1. Write the equation for the half-reaction.

Mg²⁺ + 2e⁻ ⟶ Mg

The number of electrons transferred (z) is 2 mol per mole of Mg.

2. Calculate the number of coulombs

Q  = It  

\text{t} = \text{90 min} \times \dfrac{\text{60 s}}{\text{1 min}} = \text{5400 s}\\\\Q = \text{3 C/s} \times \text{ 5400 s} = 16 000 C

3. Mass of Mg

We can summarize Faraday's laws as

m = \dfrac{QM}{zF}\\\begin{array}{rcl}m & = &\dfrac{16 000 \times 24.30}{2 \times 96 485}\\& = & \textbf{2.0 g}\\\end{array}\\\text{The mass of Mg deposited is }\boxed{\textbf{2.0 g}}

8 0
3 years ago
In Universe L, recently discovered by an intrepid team of chemists who also happen to have studied interdimensional travel, quan
Advocard [28]

Answer:

Manganese, Fifth transition element

[X] 3d⁶ 4s¹

Iron, Sixth transition element

[X] 3d⁶ 4s²

Explanation:

Complete Question

In Universe L, recently discovered by an intrepid team of chemists who also happen to have studied interdimensional travel, quantum mechanics works as it does in our universe, except that there are six d orbitals instead of the usual number we observe here. Use these facts to write the ground-state electron configurations of the sixth and seventh elements in the first transition series in Universe L. Note; you may use [X] to stand for the electron configuration of the noble gas at the end of the row before the first transition series.

Solution

In our universe, there are 5 d orbitals.

And according to Aufbau's principles that electrons fill the lower energy orbitals before they fill higher energy orbitals and Hund's Rule that states that electrons are fed singly to all the orbitals of a subshell before pairing occurs.

The fifth and sixth transition elements in our universe is then Manganese and Iron respectively.

Manganese - [Ar] 3d⁵ 4s²

Iron - [Ar] 3d⁶ 4s²

So, in the new universe L, where there are six d orbitals, for manganese, the fifth transition metal, because half filled orbitals are more stable than partially filled orbitals (that woukd have been rhe case if we leave 5 electrons on the 3d orbital), the 4s orbital is filled to half of its capacity and the one electron removed from the 4s is used to fill the six 3d orbital to half of its capacity too.

For the sixth transition element, the new extra electron just fills the lower energy 4s orbital, leaving the six 3d orbitals all half-filled.

Hence, they both have ground state configurations of

- Manganese, Fifth transition element

[X] 3d⁶ 4s¹

- Iron, Sixth transition element

[X] 3d⁶ 4s²

Hope this Helps!!!

7 0
3 years ago
The mass of a solid is 3.60 grams and its volume is 1.8 cubic centimeters. What is the density of the solid, expressed to the co
andrew-mc [135]
Density is ratio of mass and volume.
therefore Density is equal to mass/ volume
but mass =3.60gand volume =1.8cm3
therefore density is equal to 3.60/1.8
density = 2.0gcm3

7 0
3 years ago
Read 2 more answers
The basic fact that determines molecular shapes is that
Alinara [238K]

Answer:

The shape of a molecule is mostly determined by repulsion among the pairs of electrons around a central atom.

4 0
3 years ago
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