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valentinak56 [21]
3 years ago
15

A record turntable is rotating at 33 1 3 rev/min. a watermelon seed is on the turntable 5.0 cm from the axis of rotation. (a) ca

lculate the acceleration of the seed, assuming that it does not slip. (enter the magnitude.)
Physics
2 answers:
kvv77 [185]3 years ago
8 0
Since the motion is rotational, we can associate this with centrifugal/centripetal acceleration. The formula for this is:

a = v²/r = (rω)²/r = rω²
where ω is the angular velocity and r is the radius

Let's convert v in terms of rad/min. The conversion from rev to rad is, 1 rev = 360° = 2π. So,
ω = 33 1/3 rev/min * 2π rad/1 rev = 209.44 rad/min

a = 5 cm(209.44 rad/min)²
<em>a = 219,325.568 cm/min²</em>
LenaWriter [7]3 years ago
4 0
Distance D = 5 cm = 0.05m 
Revolutions = 33.33 per min => t = 60 sec 
Acceleration is v^2 / r, so first we need to find velocity 
Velocity = (D x 3.14 x r) / t => (0.05 x 3.14 x 33.33) / 60 
Velocity = 0.0872 m/s 
Acceleration = v^2 / r = 0.0872^2 / 0.05 = 0.152.
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